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Re: If 0 < x < 1, which of the following inequalities must be [#permalink]
08 Oct 2008, 07:36

My two cents:

I beeter if you divided by x^2: x^2+x^3<x+1 -> always II better if you divided by x^2: x^2-x^3<1-x^2 always III dividing by x^2: x^2-x^3<1-x^2 if x=0.1 thus 0.01-0.001<1-0.01 always if x=0.9 thus 0.81-0.729<1-0.9 // 0.081<1 always

Re: If 0 < x < 1, which of the following inequalities must be [#permalink]
08 Oct 2008, 08:01

I also believe the answer is E since even the third equation, x^4 - x^5 < x^2 - x^3 = x^4 + x^3 < x^2 + x^5 =x^2 + x < 1+x^3 which is true since the value on the right hand side will be greater than 1.

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