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if (1+ 1/r)x=1, then what does x equal in terms of r?

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if (1+ 1/r)x=1, then what does x equal in terms of r?  [#permalink] New post 20 Dec 2003, 22:04
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if (1+ 1/r)x=1, then what does x equal in terms of r?



Please explain





>>>> answer is r/(r+1) >>>>>>
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Re: PS - algebra [#permalink] New post 20 Dec 2003, 22:15
ftoor wrote:
if (1+ 1/r)x=1, then what does x equal in terms of r?




do I really need to explain?? cross-multiply and solve for x
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 [#permalink] New post 20 Dec 2003, 22:35
dj, don't be a jerk. ftoor is having some problems with algebra, and I'm sure he doesn't need your snarky comments...


"if (1+ 1/r)x=1, then what does x equal in terms of r"

Simply divide both sides of the equation by (1+ 1/r), isolating X.

then, on the other side of the equation, you get 1/(1+ 1/r)

So you've solved for x. Now you need to simplfy.

Since you have a fraction, you can multiply the top by whatever you'd like, as long as you multiply the bottom. The thorny part of this expression is the 1/r part, so lets multiply the top and bottom of the fraction by r.

Top of the fraction is 1. 1*r=r

Bottom of the fraction is (1+ 1/r). Multiply both terms by r, and you get r+(r/r), which reduces to r+1

hence, 1/(r+1)


Send me a private message if this doesn't make sense.
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 [#permalink] New post 20 Dec 2003, 23:25
stoolfi wrote:
dj, don't be a jerk. ftoor is having some problems with algebra, and I'm sure he doesn't need your snarky comments...


"if (1+ 1/r)x=1, then what does x equal in terms of r"

Simply divide both sides of the equation by (1+ 1/r), isolating X.

then, on the other side of the equation, you get 1/(1+ 1/r)

So you've solved for x. Now you need to simplfy.

Since you have a fraction, you can multiply the top by whatever you'd like, as long as you multiply the bottom. The thorny part of this expression is the 1/r part, so lets multiply the top and bottom of the fraction by r.

Top of the fraction is 1. 1*r=r

Bottom of the fraction is (1+ 1/r). Multiply both terms by r, and you get r+(r/r), which reduces to r+1

hence, 1/(r+1)


Send me a private message if this doesn't make sense.


hard words were never intended. ftoor, excuse me if I acted snobbishly.

did that showed my schizophrenic aspect :roll:
  [#permalink] 20 Dec 2003, 23:25
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