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If (1/5)^m * (1/4)^18 = 1/2(10)^35 then m = a) 2 b) 13 c) 17

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If (1/5)^m * (1/4)^18 = 1/2(10)^35 then m = a) 2 b) 13 c) 17 [#permalink] New post 17 Oct 2007, 07:38
If (1/5)^m * (1/4)^18 = 1/2(10)^35 then m =
a) 2
b) 13
c) 17
d) 34
e) 35
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 [#permalink] New post 17 Oct 2007, 07:45
i cannot understand the right side of the equation, could you use proper syntax? thx
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 [#permalink] New post 17 Oct 2007, 07:59
the right side should be 1/(2(10)^35)

or

1 divided by 2 times 10 to the 35th power

I hope this makes it clearer
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 [#permalink] New post 17 Oct 2007, 08:00
how did you get to 35?
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 [#permalink] New post 17 Oct 2007, 18:15
I'm stuck on this one ...

You can re-write the right hand side to say

1/(20^35) => 1/((4^35)*(5^35)), which re-writes to 1/(4^35) * 1/(5^35) ...

And if the left side is 1/(5^m) * 1/(4^18), we need 'super math' (ie a calculator to figure it out, n'est pas?
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 [#permalink] New post 18 Oct 2007, 12:21
I agree Big-O. This one still has me confused.

Can someone please walk through the steps on this problem?
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 [#permalink] New post 18 Oct 2007, 13:00
flood wrote:
I agree Big-O. This one still has me confused.

Can someone please walk through the steps on this problem?


It was hard to find it ;)

Have a look at this one : http://www.gmatclub.com/forum/t42550

Also, here... http://www.gmatclub.com/forum/p297974
  [#permalink] 18 Oct 2007, 13:00
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If (1/5)^m * (1/4)^18 = 1/2(10)^35 then m = a) 2 b) 13 c) 17

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