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If 10^50 - 74 is written as an integer in base 10 notation,

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Director
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If 10^50 - 74 is written as an integer in base 10 notation, [#permalink] New post 30 Jun 2005, 18:32
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C
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If 10^50 - 74 is written as an integer in base 10 notation, what is the sum of the digits in that integer?
A. 424
B. 433
C. 440
D. 449
E. 467

Explanations please
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 [#permalink] New post 30 Jun 2005, 18:44
10^50 is 1 followed by 50 zeros.

10^50 - 74 = 999...926

The 9s occur 50-2 = 48 times.

Sum of digits = 48*9+6+2 = 440

C
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Re: PS [#permalink] New post 30 Jun 2005, 18:48
rthothad wrote:
If 10^50 - 74 is written as an integer in base 10 notation, what is the sum of the digits in that integer?
A. 424
B. 433
C. 440
D. 449
E. 467

Explanations please


I got C.

10^50 has 1 followed by 50 zeroes.
10^50 - 74 has 48 9's with 26 at the last two places.
sum of the digits = 48*9 + 8 = 440.

HMTG.
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 [#permalink] New post 30 Jun 2005, 18:50
OA is C.

Thanks guys. I was trying 48*9 + 26 and coming up with no match, I guess I must call it a day.
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Re: PS [#permalink] New post 30 Jun 2005, 18:51
rthothad wrote:
If 10^50 - 74 is written as an integer in base 10 notation, what is the sum of the digits in that integer?
A. 424
B. 433
C. 440
D. 449
E. 467. Explanations please


10^2-74=100-74 = 26
10^3-74=1,000-74 = 926
10^4-74=10,000-74 = 9926
.
.
.
10^50-74= fortyeight 9's and 26= 48X9+26= the last digit is zero so it should be 440.
Re: PS   [#permalink] 30 Jun 2005, 18:51
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