Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

If 12 ounces of a strong vinegar solution are diluted with [#permalink]

Show Tags

19 Jul 2010, 00:07

2

This post received KUDOS

9

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

45% (medium)

Question Stats:

67% (02:51) correct
33% (01:58) wrong based on 392 sessions

HideShow timer Statistics

If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a three-percent vinegar solution, what was the concentration of the original solution?

If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a three-percent vinegar solution, what was the concentration of the original solution?

19.3% 17% 16.67% 15.5% 12.5%

Let the concentration of the original solution be \(x%\).

\(3%\) of vinegar in \(50+12=62\) ounces of vinegar solution came from \(12\) onces of \(x%\) strong vinegar solution (as in 50 ounces of water there is no vinegar at all), so: \(12*x=0.03(12+50)\) --> \(x=0.155=15.5%\).

Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

Show Tags

27 Sep 2012, 13:40

1

This post received KUDOS

Let X be the quantity of non-vinegar in the strong vvinegar solution Thus vinegar quantity will be 12 - X When 50 ounces of water were added the percentage of vinegar becomes 3%, thus (12 - X)/62 = 3/100 From this equation X = 10.14 Answer (12-10.14)/12 = 15.5%

Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

Show Tags

13 May 2013, 23:16

Vinegar Quantity = 12 ounces(x% of concentration) = percentage of vinegar in water vinegar mixture i.e, 12*x/100 = 3*(50+12)/100 x=15.5 % Original vinegar concentration

Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

Show Tags

20 Sep 2013, 14:28

bibha wrote:

If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a three-percent vinegar solution, what was the concentration of the original solution?

A. 19.3% B. 17% C. 16.67% D. 15.5% E. 12.5%

This is a type of question where homogenous solution(Water) is mixed with a mixture Therefore concentration is inversely proportional to volume i.e Concentation(final) X Volume(Final) = Concentration(initial) X volume(initial) 0.3 X 62 = Concentration(initial) X 12 Concentration (initial) = 15.5% Hence D

Let the total volume is v ounces, hence we need to find out (12/v)*100. When 50 ounces of water is added the total volume is increased to V+50

Given (12/v+50) * 100 = 3 on solving we get v=350. hence 12/350 * 100 = 3.4

Can some one tell me whats wrong in this way?

What has the volume has to do with the problem?

50 ounces of 0% solution (water) is added to 12 ounces of x% solution, resulting in 62 ounces of 3% solution. The question asks to find the value of x.

Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

Show Tags

23 Mar 2015, 06:53

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Re: If 12 ounces of a strong vinegar solution are diluted with [#permalink]

Show Tags

02 May 2016, 10:20

bibha wrote:

If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a three-percent vinegar solution, what was the concentration of the original solution?

A. 19.3% B. 17% C. 16.67% D. 15.5% E. 12.5%

Initially the volume=12 ounces later we add 50ounces water to get final volume =50+12 =62 ounces. Concentration of vinegar in final solution=3% As amount of vinegar is same as before or after dilution A=C*V 12*x%=62*3% X=15.5% Ans D

After days of waiting, sharing the tension with other applicants in forums, coming up with different theories about invites patterns, and, overall, refreshing my inbox every five minutes to...

I was totally freaking out. Apparently, most of the HBS invites were already sent and I didn’t get one. However, there are still some to come out on...

In early 2012, when I was working as a biomedical researcher at the National Institutes of Health , I decided that I wanted to get an MBA and make the...