sperumba wrote:

If 2 different representatives are to be selected at random from a group of 10 employees and if p is the probability that both representatives selected will be women, is p > 1/2?

(1)More than 1/2 of the 10 employees are women.

(2)The probability that both representatives selected will be men is less than 1/10 .

'E'!

St1: More than 1/2 of the 10 employees are women.

For 5 women,

p = 5C2/10C2 = ~0.2

If No. of women > 5, p will increase. YES/NO

St2:The probability that both representatives selected will be men is less than 1/10

We can't get 'p' from this information. YES/NO

since 1-(1/10) is not only 'p' but also prob of 1 man + 1 woman

Together:

YES/NO.

So, it should be 'E'