getzgetzu wrote:

If 2^N is a factor of a certain number, the greatest value of N is the 2-height of the number. Which of M and K has the greater 2-height?

1). K>M

2). K/M is an even number.

1. K=9>M=8

2^0=1 is a factor of K

2^3=8 is a factor of K

---> 2-height of K is smaller than that of M

K=8, M=2

2-height of K is bigger than that of M

---->insuff

2. since 2^N is

a factor of number ---> 2^N must be > 0

There're two cases: both K and M are even, K is even and M is odd

in case : both K and M are even:

since K/M= even number ----> K is a multiple of M --> K= M*2l

2-height of M is 2^y----> K= 2^y * t (t is integer) * 2l = tl* 2^(y+1)

-->2-height of K is y+1, that of M is y ---> 2-height of L is > that of M

in case K is even and M is odd ---> 2-height of M is 0

2-height of K (since K is even) must be >0

----> 2-height of K> that of M

both cases yield the same result --->suff

Hik,i hurry to bathe now ( no more hot water if late) ..it's clumsy , hope you get what i explain

...anyway, i'll re-check my reasoning