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If 2^x-2^{(x-2)} = 3*2^{13} , what is the value of x

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If 2^x-2^{(x-2)} = 3*2^{13} , what is the value of x [#permalink] New post 18 Jan 2006, 22:07
If 2^x-2^{(x-2)} = 3*2^{13} , what is the value of x


a. 9
b. 11
c. 13
d. 15
e. 17

I can get the answer by plugging in answer choices but I would like to understand how to correctly derive the answer.

Last edited by timetrader on 18 Jun 2009, 17:04, edited 1 time in total.
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Re: exponents [#permalink] New post 18 Jan 2006, 22:15
vbang wrote:
If 2^x-2^x-2 = 3(2^13) , what is the value of x


a. 9
b. 11
c. 13
d. 15
e. 17

I can get the answer by plugging in answer choices but I would like to understand how to correctly derive the answer.

2^x-2^x-2=3(2^13)
2^x-2(2^2-1)=3*2^13
2^x-2*(4-1)=3*2^13
2^x-2=2^13
x-2=13
x=15
D it is
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Re: exponents [#permalink] New post 18 Jan 2006, 22:25
vbang wrote:
If 2^x-2^x-2 = 3(2^13) , what is the value of x
a. 9
b. 11
c. 13
d. 15
e. 17
I can get the answer by plugging in answer choices but I would like to understand how to correctly derive the answer.

which one is your question?

1. (2^x) - 2^(x-2) = 3(2^13)
2. (2^x) - (2^x) -2 = 3(2^13)
3. 2^(x-2)^(x-2) = 3(2^13)
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 [#permalink] New post 18 Jan 2006, 23:15
ambiguish question :roll:
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 [#permalink] New post 19 Jan 2006, 03:39
Ambiguous question. Could be interpreted inmany ways without parentheses.
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 [#permalink] New post 19 Jan 2006, 03:55
ps_dahiya wrote:
Ambiguous question. Could be interpreted inmany ways without parentheses.

Agree but this quest discussed recently so the stem should be
2^x-(2^(x-2)) = 3(2^13) Hope this helps
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 [#permalink] New post 19 Jan 2006, 08:33
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2^x-(2^(x-2)) = (2^x)*[1-2^(-2)]= (2^x)*(3/4)=3* [2^x*2^(-2)]=3* [2^(x-2)]

so. x-2 =13 => x=15
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 [#permalink] New post 19 Jan 2006, 10:05
Now this becomes solvable... :)

2^x(1-2^-2) = 2^x * 3/4 = 3*2^(x-2) => x-2 = 13 => x=11
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 [#permalink] New post 19 Jan 2006, 11:20
chiragr wrote:
Now this becomes solvable... :)

2^x(1-2^-2) = 2^x * 3/4 = 3*2^(x-2) => x-2 = 13 => x=11

where did the 3/4 on the left side and 3 on the right side gone?
And in this kind of question it is easier to take out of parentheses the smallest exp try it
and X-2=13--->X=15
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 [#permalink] New post 19 Jan 2006, 12:17
I would strongly suggest every body to use () the right way ..
so that we can understand questions better.
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 [#permalink] New post 19 Jan 2006, 19:42
I got 15, and then on the second thought found the ambiguity.
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 [#permalink] New post 20 Jan 2006, 00:20
chiragr wrote:
Now this becomes solvable... :)

2^x(1-2^-2) = 2^x * 3/4 = 3*2^(x-2) => x-2 = 13 => x=11



Boy these mistakes will kill me on the first question it self...
x-2 =13 =>x=11? what was I thinking!
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 [#permalink] New post 20 Jan 2006, 00:28
chiragr wrote:
chiragr wrote:
Now this becomes solvable... :)

2^x(1-2^-2) = 2^x * 3/4 = 3*2^(x-2) => x-2 = 13 => x=11



Boy these mistakes will kill me on the first question it self...
x-2 =13 =>x=11? what was I thinking!

Good that you on this forum)))
we all here to learn not to do this kind of mistakes!
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 [#permalink] New post 25 Jan 2006, 04:20
D without taking into consideration any paranthesis.
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 [#permalink] New post 25 Jan 2006, 10:14
vbang do you copy us :peek
Please come back and correct this convoluted question and give breather to guys here :P
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 [#permalink] New post 25 Jan 2006, 12:46
15 after assuming the paranthesis. Otherwise, no answer.
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 [#permalink] New post 25 Jan 2006, 13:29
x = 15
Yurik79's approach
  [#permalink] 25 Jan 2006, 13:29
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