kook44 wrote:

giddi77, can you explain how

2^x-2^(x-2)

reduces to

2^(x-2) [2^2 - 1]

and then

2^(x-2) * 3

OK 2^x can be written as 2^(x

+2-2) = 2^(

x-2) * 2

^2.

Hence 2^x - 2^(x-2) = 2^(x-2)* 2^2 - 2^(x-2) = 2^(x-2) [ 2^2 -1] by taking out the common factor 2^(x-2)

HTH.

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