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Re: If -2x >3y , is x negative ? [#permalink]
15 Jul 2008, 10:31

1) Sufficient y> 0 meant -x > +ve value; x is negative. 2) 2x + 5y = 20; given: 2x<-3y so if 2x=-10y then -10y+5y=20; y<0 but if 2x=-4x then -4y+5y=20; y>0 Not sufficient.

Re: If -2x >3y , is x negative ? [#permalink]
17 Jul 2008, 09:39

MamtaKrishnia wrote:

OA is D ..

fresinha12 wrote:

i am getting D... lets see (2) 2x+5y-20=0 2x=20-5y

we are told that -2x>3y

-2x=5y-20

5y-20>3y 2y>20 y>10..

if y is positive than -2x>3y x has to be negative

Thanks fresinha12.. Its a very good explanation

I think you guys (and possibly girls) or making this harder than it really is. Anytime you have a given equality with 2 variables and one inequality with 2 variables do the following:

If -2x > 3y, is x negative?

(1) we already know this is sufficient

(2) 2x + 5y -20 = 0 ---> solve this for y 5y = 20 - 2x -----> y = (20 - 2x)/5 --> substitute y in for y in the inequality up above: -2x > 3*((20 - 2x)/5) ----> -2x > (60 - 2x)/5 ---> -10x > 60 - 2x ----> -8x > 60 (divide by -8 so switch sign around) ---> x < -7.5 ---> x is definitely negative: SUFFICIENT

Answer: D

_________________

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gmatclubot

Re: If -2x >3y , is x negative ?
[#permalink]
17 Jul 2008, 09:39