If -2x >3y , is x negative ? 1) y>0 2) 2x+52-20=0 I : Quant Question Archive [LOCKED]
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# If -2x >3y , is x negative ? 1) y>0 2) 2x+52-20=0 I

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Manager
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If -2x >3y , is x negative ? 1) y>0 2) 2x+52-20=0 I [#permalink]

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15 Jul 2008, 08:39
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If -2x >3y , is x negative ?
1) y>0
2) 2x+52-20=0

I solved this Q by trial and error method
Wanted to know a better method for solving this this Q ..
Director
Joined: 27 May 2008
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Re: If -2x >3y , is x negative ? [#permalink]

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15 Jul 2008, 08:49
MamtaKrishnia wrote:
If -2x >3y , is x negative ?
1) y>0
2) 2x+52-20=0

I solved this Q by trial and error method
Wanted to know a better method for solving this this Q ..

could you please recheck the statement 2. looks like a typo...
Manager
Joined: 02 May 2008
Posts: 87
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Kudos [?]: 160 [0], given: 0

Re: If -2x >3y , is x negative ? [#permalink]

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15 Jul 2008, 08:51
durgesh79 wrote:
MamtaKrishnia wrote:
If -2x >3y , is x negative ?
1) y>0
2) 2x+52-20=0

I solved this Q by trial and error method
Wanted to know a better method for solving this this Q ..

could you please recheck the statement 2. looks like a typo...

yeah Sorry!!!
statement 2 is
2) 2x+5y-20=0
Director
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Re: If -2x >3y , is x negative ? [#permalink]

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15 Jul 2008, 09:04
MamtaKrishnia wrote:
durgesh79 wrote:
MamtaKrishnia wrote:
If -2x >3y , is x negative ?
1) y>0
2) 2x+52-20=0

I solved this Q by trial and error method
Wanted to know a better method for solving this this Q ..

could you please recheck the statement 2. looks like a typo...

yeah Sorry!!!
statement 2 is
2) 2x+5y-20=0

doesnt matter
i think the answer should be A,
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Re: If -2x >3y , is x negative ? [#permalink]

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15 Jul 2008, 09:46
Answer is (A) since the question asks you whether or not x < -3/2 y holds true

If y>0, then -3/2 y < 0 ==> x<0
SVP
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Re: If -2x >3y , is x negative ? [#permalink]

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15 Jul 2008, 10:21
I get A as well.

from stat 2, the answer could go either way depending on conditions on y, which we dont know. ..
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Re: If -2x >3y , is x negative ? [#permalink]

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15 Jul 2008, 10:31
1) Sufficient y> 0 meant -x > +ve value; x is negative.
2) 2x + 5y = 20; given: 2x<-3y
so if 2x=-10y then -10y+5y=20; y<0
but if 2x=-4x then -4y+5y=20; y>0
Not sufficient.

A.
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Re: If -2x >3y , is x negative ? [#permalink]

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15 Jul 2008, 13:00
i am getting D...
lets see (2)
2x+5y-20=0
2x=20-5y

we are told that -2x>3y

-2x=5y-20

5y-20>3y
2y>20
y>10..

if y is positive than -2x>3y x has to be negative
Director
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Re: If -2x >3y , is x negative ? [#permalink]

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16 Jul 2008, 00:43
1
KUDOS
D it is...

in the below pic

1. overlapping area of yellow and blue, x < 0
2. line segament in red, x<0
Attachment:

DS Q2.JPG [ 15.18 KiB | Viewed 1649 times ]
Manager
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Re: If -2x >3y , is x negative ? [#permalink]

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17 Jul 2008, 04:50
OA is D ..
fresinha12 wrote:
i am getting D...
lets see (2)
2x+5y-20=0
2x=20-5y

we are told that -2x>3y

-2x=5y-20

5y-20>3y
2y>20
y>10..

if y is positive than -2x>3y x has to be negative

Thanks fresinha12..
Its a very good explanation
Manager
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Re: If -2x >3y , is x negative ? [#permalink]

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17 Jul 2008, 09:39
MamtaKrishnia wrote:
OA is D ..
fresinha12 wrote:
i am getting D...
lets see (2)
2x+5y-20=0
2x=20-5y

we are told that -2x>3y

-2x=5y-20

5y-20>3y
2y>20
y>10..

if y is positive than -2x>3y x has to be negative

Thanks fresinha12..
Its a very good explanation

I think you guys (and possibly girls) or making this harder than it really is. Anytime you have a given equality with 2 variables and one inequality with 2 variables do the following:

If -2x > 3y, is x negative?

(1) we already know this is sufficient

(2) 2x + 5y -20 = 0 ---> solve this for y
5y = 20 - 2x -----> y = (20 - 2x)/5 --> substitute y in for y in the inequality up above:
-2x > 3*((20 - 2x)/5) ---->
-2x > (60 - 2x)/5 --->
-10x > 60 - 2x ---->
-8x > 60 (divide by -8 so switch sign around) --->
x < -7.5 ---> x is definitely negative: SUFFICIENT

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Re: If -2x >3y , is x negative ?   [#permalink] 17 Jul 2008, 09:39
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# If -2x >3y , is x negative ? 1) y>0 2) 2x+52-20=0 I

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