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# If -2x>3y, is x negative? (1) y>0 (2) 2x+5y-20=0

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Senior Manager
Joined: 27 Aug 2005
Posts: 332
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If -2x>3y, is x negative? (1) y>0 (2) 2x+5y-20=0 [#permalink]  19 Sep 2005, 18:40
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0% (00:00) correct 100% (00:00) wrong based on 1 sessions
If -2x>3y, is x negative?

(1) y>0
(2) 2x+5y-20=0
VP
Joined: 22 Aug 2005
Posts: 1123
Location: CA
Followers: 1

Kudos [?]: 42 [0], given: 0

D.

i) sufficient.
-2x > 3y if y > 0
-2x > +ve number
x has to be negative

ii)
2x+5y-20=0
simplifying:
y = (-2/5)x + 4
put into question stem:

-2x > 3 *(-2/5x + 4)

can solve for x(-ve)
Senior Manager
Joined: 15 Aug 2005
Posts: 257
Location: Las Vegas, NV
Followers: 2

Kudos [?]: 0 [0], given: 0

I got D.

Adjust the given equation to x < -3y/2

Statement one is sufficient. Any positive number multiplied by a negative number is a negative number.

Statement two is sufficient. Adjust the equation to

x = 10-(5y/2)

substitute into the original equation

10-(5y/2) < (-3y/2)

10 < y

Any positive number multiplied by a negative number is a negative number.
Intern
Joined: 16 Aug 2005
Posts: 25
Location: India
Followers: 0

Kudos [?]: 0 [0], given: 0

f -2x>3y, is x negative?

(1) y>0
(2) 2x+5y-20=0

stat 1) is obvious.

stat 2) -2x > 3y or 2x< -3y

subst in 2; -3y+5y>20 or y>10

thats why D.
Senior Manager
Joined: 27 Aug 2005
Posts: 332
Followers: 2

Kudos [?]: 39 [0], given: 0

Thanks. I still get confused about substituting inequations into equations.
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