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Re: If -2x>3y, is x negative [#permalink]
15 Feb 2010, 14:26

Ques x < 0 ?

Given -2x > 3y

S1: y > 0... implies 3y > 0 Therefore -2x > 0.... this can only happen if x < 0.. Hence SUFF

S2: 2x + 5y = 20 5y - 20 = 2x

5y - 20 > 3y 2y > 20 y > 10

Therefore -2x > 30.... this can only be possible if x < 0... Hence SUFF..

Therefore D.. _________________

Cheers! JT........... If u like my post..... payback in Kudos!!

|Do not post questions with OA|Please underline your SC questions while posting|Try posting the explanation along with your answer choice| |For CR refer Powerscore CR Bible|For SC refer Manhattan SC Guide|

Re: If -2x>3y, is x negative [#permalink]
12 Mar 2010, 03:49

-2x > 3y

stmt1: y>0 if y>0 => 3y>0 => -2x>0 => 2x<0 => x< 0 so suff to answer

stmt2: 2x+5y-20 = 0 => 2x+5y = 20 => 5y = 20 - 2x => y = (20-2x)/5 replace y in first -2x>3y

-2x>3(20-2x)/5 => -10x>60-6x =>-4x>60 =>-x>15 =>x<-15 (multiply by -1 both the sides and change the inequalities) if x<-15 it is sure that x<0 also so suff hence, both alone can determine the answer _________________

Re: If -2x>3y, is x negative [#permalink]
17 Jul 2014, 02:57

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Re: If -2x>3y, is x negative [#permalink]
17 Jul 2014, 04:40

1

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Expert's post

If -2x>3y , is x negative

Given: -2x>3y. Question: is x<0? (Note here that if y is any positive number then we would have -2x>positive, and in order that to be true x must be some negative number).

(1) y>0 --> -2x>3y>0 --> x<0. Sufficient.

(2) 2x+5y-20=0 --> 2x=20-5y --> -20+5y>3y --> y>10. The same as above: x<0. Sufficient.

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