If 2x - 4y = -2 and 3x - 2y = 3, then 2y+x = (A) 3/2 (B) 2

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Director

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If 2x - 4y = -2 and 3x - 2y = 3, then 2y+x = (A) 3/2 (B) 2 [#permalink]

20 Oct 2006, 11:24

If 2x - 4y = -2 and 3x - 2y = 3, then 2y+x =

(A) 3/2
(B) 2
(C) 3.5
(D) 5
(E) 5.5

I know what the answer is now. Originally, I tried solving for x and y 1st. From what I understand, that was the wrong way to go about this. How do you know when to try solving for x and y as opposed to simply subtracting one equation from the other? I don't want to waste valuable time discovering this on G Day.

Manager

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Re: Tricky Question .... for me [#permalink]

20 Oct 2006, 11:37

I am getting the answer as 5 both ways. By solving for x and y as well as by subtracting one from the other.

Director

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Re: Tricky Question .... for me [#permalink]

20 Oct 2006, 12:01

ggarr wrote:

1)subtracting one equation from the other
2x - 4y = -2
3x - 2y = 3
2x-(-3x)-4y-(-2y)=-2-3
-x-2y=-5 multiply both sides by -1 and get
2y+x=5
Total 45 secs
2) about 1.5 min
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[#permalink]

20 Oct 2006, 12:23

If 2x - 4y = -2 and 3x - 2y = 3, then 2y+x =

(A) 3/2
(B) 2
(C) 3.5
(D) 5
(E) 5.5

combo question

2x-4y = -2 multiply by -1

4y-2x = 2
3x-2y = 3 add both together

2y+x = 5 d is my answer

Director

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20 Oct 2006, 12:26

This is what I did originally:

a) 2x - 4y= -2/-2 ---> -x + 2y = 1

b) 3x - 2y = 3/3 ---> x - 2/3y = 1

c) x - 2/3y = -x + 2y

d) -3x + 6y = 3x - 2y

e) 8y = 6x

Where did I go wrong?

Director

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21 Oct 2006, 16:59

Yes. Your explanation was very helpful. Thanks

Director

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21 Oct 2006, 21:48

-2y + 3x = 3 -----A
-4y + 2x = -2 ------B
+ - +
Subtracting B from A.

----------------------------
2y + x = 5

C.

[#permalink] 21 Oct 2006, 21:48

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If 2x - 4y = -2 and 3x - 2y = 3, then 2y+x = (A) 3/2 (B) 2

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If 2x - 4y = -2 and 3x - 2y = 3, then 2y+x = (A) 3/2 (B) 2

If 2x - 4y = -2 and 3x - 2y = 3, then 2y+x = (A) 3/2 (B) 2

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