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If 3^k + 3^k = (3^9)^(3^9) - 3^k, then k = ?

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If 3^k + 3^k = (3^9)^(3^9) - 3^k, then k = ? [#permalink] New post 17 Jan 2006, 11:06
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68% (02:56) correct 33% (01:40) wrong based on 39 sessions
If 3^k + 3^k = (3^9)^(3^9) - 3^k, then k = ?

(A) 11/3
(B) 11/2
(C) 242
(D) 3^10
(E) 3^11 - 1
[Reveal] Spoiler: OA

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Last edited by Bunuel on 01 Sep 2014, 01:54, edited 2 times in total.
Renamed the topic, edited the question, added the OA and moved to PS forum.
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Re: If 3^k + 3^k = (3^9)^(3^9) - 3^k, then k = ? [#permalink] New post 17 Jan 2006, 12:13
C.

3^k + 3^k = 2.3^k = ((3^9)^3*9) - 3^k.
3.3^k = ((3^(9*27))

Thus, K+1 = 9*27 = 243.

Thus, k = 242.
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Re: If 3^k + 3^k = (3^9)^(3^9) - 3^k, then k = ? [#permalink] New post 17 Jan 2006, 12:25
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3^k + 3^k = (3^9)^3^9 - 3^k

3*(3^k) = 3 ^ (9 * 3^9 ) = 3^(3^2 * 3^9) = 3^(3^11)

3^k+1 = 3^(3^11)

So k+1 = 3^11

So k = 3^11 -1

Answer is E
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Re: If 3^k + 3^k = (3^9)^(3^9) - 3^k, then k = ? [#permalink] New post 17 Jan 2006, 13:58
Its E

(3^11) -1

Giddi77,

Initially I got confused because answer choice E is 311 -1 instead of 3^11 -1.
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Re: If 3^k + 3^k = (3^9)^(3^9) - 3^k, then k = ? [#permalink] New post 17 Jan 2006, 14:19
looks like giddi forgot the 3^11
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Re: If 3^k + 3^k = (3^9)^(3^9) - 3^k, then k = ? [#permalink] New post 17 Jan 2006, 15:13
ps_dahiya wrote:
Its E

(3^11) -1

Giddi77,

Initially I got confused because answer choice E is 311 -1 instead of 3^11 -1.


Sir you are right! I have edited the question. It was an artifact of the copy and paste in the browser. Sorry about that.
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Re: If 3^k + 3^k = (3^9)^(3^9) - 3^k, then k = ? [#permalink] New post 17 Jan 2006, 19:02
Yes got E after some struggle. Very nice question.
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Re: If 3^k + 3^k = (3^9)^(3^9) - 3^k, then k = ? [#permalink] New post 17 Jan 2006, 21:41
yups E it is...
cud guess the value by just looking at the choices but took almost 4 min to get the real value
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Re: If 3^k + 3^k = (3^9)^(3^9) - 3^k, then k = ? [#permalink] New post 24 Jan 2006, 06:29
Good question. Couldn't figure it out but learned a lot.

Thanks.
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Re: If 3^k + 3^k = (3^9)^(3^9) - 3^k, then k = ? [#permalink] New post 30 Aug 2014, 23:53
chiragr wrote:
3^k + 3^k = (3^9)^3^9 - 3^k

3*(3^k) = 3 ^ (9 * 3^9 ) = 3^(3^2 * 3^9) = 3^(3^11)

3^k+1 = 3^(3^11)

So k+1 = 3^11

So k = 3^11 -1

Answer is E



Can you explain the LHS part of this equation? How did you get k+1 ?
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Re: If 3^k + 3^k = (3^9)^(3^9) - 3^k, then k = ? [#permalink] New post 01 Sep 2014, 01:55
Expert's post
AkshayDavid wrote:
chiragr wrote:
If 3^k + 3^k = (3^9)^(3^9) - 3^k, then k = ?

(A) 11/3
(B) 11/2
(C) 242
(D) 3^10
(E) 3^11 - 1

3^k + 3^k = (3^9)^3^9 - 3^k

3*(3^k) = 3 ^ (9 * 3^9 ) = 3^(3^2 * 3^9) = 3^(3^11)

3^k+1 = 3^(3^11)

So k+1 = 3^11

So k = 3^11 -1

Answer is E



Can you explain the LHS part of this equation? How did you get k+1 ?


3*3^k = 3^(k+1).

Hope it's clear.
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Re: If 3^k + 3^k = (3^9)^(3^9) - 3^k, then k = ? [#permalink] New post 01 Sep 2014, 19:09
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3^k + 3^k = (3^9)^{(3^9)} - 3^k

3 * 3^k = 3^{(3^2 * 3^9)}

3^{k+1} = 3^{(3^{11})}

Equating the powers as bases are same

k + 1 = 3^{11}

k = 3^{11} - 1

Answer = E
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Re: If 3^k + 3^k = (3^9)^(3^9) - 3^k, then k = ?   [#permalink] 01 Sep 2014, 19:09
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