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If 4 points are indicated on a line and 5 points are

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If 4 points are indicated on a line and 5 points are [#permalink] New post 16 May 2012, 06:52
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If 4 points are indicated on a line and 5 points are indicated on another line that is parallel to the first line, how many triangles can be formed whose vertices are among the 9 points?

A. 20
B. 30
C. 40
D. 70
E. 90

Tried doing a few options, but couldn't get it right and the answer provided left me more confused!
[Reveal] Spoiler: OA
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Re: If 4 points are indicated on a line and 5 points are [#permalink] New post 16 May 2012, 07:58
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alexpavlos wrote:
If 4 points are indicated on a line and 5 points are indicated on another line that is parallel to the first line, how many triangles can be formed whose vertices are among the 9 points?

A. 20
B. 30
C. 40
D. 70
E. 90

Tried doing a few options, but couldn't get it right and the answer provided left me more confused!


Approach #1:
There are two types of triangles possible:
With two vertices on the line with 4 points and the third vertex on the line with 5 points --> C^2_4*C^1_5=30;
With two vertices on the line with 5 points and the third vertex on the line with 4 points --> C^2_5*C^1_4=40;

Total: 30+40=70.

Answer: D.

Approach #2:

All different 3 points out of total 4+5=9 points will create a triangle EXCEPT those 3 points which are collinear.
C^3_{9}-(C^3_4+C^3_5)=84-(4+10)=70 (where C^3_4 and C^3_4 are # of different 3 collinear points possible from the line with 4 points and the line with 5 points, respectively).

Answer: D.

Hope it's clear.
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Re: If 4 points are indicated on a line and 5 points are indicat [#permalink] New post 16 May 2012, 07:04
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say line A with 4 points and line B with 5 points. and triangle is PQR.
If P is on line A and QR on line B we can have 4C1*5C2=40 triangles.
If P is on line B and QR on line A we can have 4C2*5C1=30 triangles.
Total =70 triangles.
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Re: If 4 points are indicated on a line and 5 points are [#permalink] New post 29 Dec 2012, 01:27
Not that fun this question :( I wonder how often I would see such a question on test day.

Solution:

* * * * * (line B)

* * * * (line A)

Choose 2 points from line A and a point from line B: = 4!/2!2! * 5!/1!4! = 30
Choose 1 point from line A and 2 points from line B: = 4!/1!3! * 5!/2!3! = 4 * 10 = 40

Combine possiblities: 30 + 40 = 70
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If 4 points are indicated on a line and 5 points are [#permalink] New post 18 Feb 2013, 12:30
If 4 points are indicated on a line and 5 points are indicated on another line that is parallel to the first line,how many triangles can be formed whose vertices are among the 9 points?
(A)20
(B)30
(C)40
(D)70
(E)90

Need explanation.............
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Re: If 4 points are indicated on a line and 5 points are [#permalink] New post 18 Feb 2013, 12:34
mun23 wrote:
If 4 points are indicated on a line and 5 points are indicated on another line that is parallel to the first line,how many triangles can be formed whose vertices are among the 9 points?
(A)20
(B)30
(C)40
(D)70
(E)90

Need explanation.............


Merging similar topics. Please refer to the solutions above.
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PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. NEW!!!

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set. NEW!!!


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Re: If 4 points are indicated on a line and 5 points are   [#permalink] 18 Feb 2013, 12:34
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