Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: If 75 percent of the guests at a certain banquet ordered des [#permalink]
04 Feb 2012, 23:54

2

This post received KUDOS

Expert's post

Since this is DS, and no numerical answer is required, you can also use a theoretical approach:

Stem: We know that 75% of the guests ordered dessert, but this tells us nothing about what percent ordered coffee. It could be anywhere from 0% to 100%.

1) This tells us about the dessert eaters who ordered coffee, but what about those who didn’t order dessert (i.e. the remaining 25%)? Insufficient. 2) This tells us about the same group (coffee & dessert), only as a percentage of coffee drinkers rather than of dessert eaters. We still don’t know how many people had coffee without dessert. Insufficient.

At this point, we know enough to narrow the choices to C & E. While I’m a big fan of the double-set matrix, eliminating choices this way is good exercise, too. After all, we want to focus on what kind of information would be sufficient to solve the problem. Now let’s try combining statements:

1&2) We now know two things about the same group. This is often a good sign that we can solve. In this case, we can find the number of people in this group (60% of 75 = 45), and we know what percent of the coffee drinkers it represents. We can certainly solve this (45=.9C, C=50), but we don’t need to. We know that we have the ability to calculate the number, and that this number is 90% of the target number. That’s all we need to know. Sufficient. _________________

Dmitry Farber | Manhattan GMAT Instructor | New York

Re: If 75 percent of the guests at a certain banquet ordered des [#permalink]
20 Sep 2013, 22:07

DmitryFarber wrote:

Since this is DS, and no numerical answer is required, you can also use a theoretical approach:

Stem: We know that 75% of the guests ordered dessert, but this tells us nothing about what percent ordered coffee. It could be anywhere from 0% to 100%.

1) This tells us about the dessert eaters who ordered coffee, but what about those who didn’t order dessert (i.e. the remaining 25%)? Insufficient. 2) This tells us about the same group (coffee & dessert), only as a percentage of coffee drinkers rather than of dessert eaters. We still don’t know how many people had coffee without dessert. Insufficient.

At this point, we know enough to narrow the choices to C & E. While I’m a big fan of the double-set matrix, eliminating choices this way is good exercise, too. After all, we want to focus on what kind of information would be sufficient to solve the problem. Now let’s try combining statements:

1&2) We now know two things about the same group. This is often a good sign that we can solve. In this case, we can find the number of people in this group (60% of 75 = 45), and we know what percent of the coffee drinkers it represents. We can certainly solve this (45=.9C, C=50), but we don’t need to. We know that we have the ability to calculate the number, and that this number is 90% of the target number. That’s all we need to know. Sufficient.

This can be solved with venn diagram

lets 100 be total, 75% ordered coffee and 60% of 75 = ordered Both.... = 45

The matrix approach is a convenient and structured way of using venn diagrams when there are 2 elements involved. The 2 mutually exclusive events ( coffee, no coffee) appear in rows, and 2 mutually exclusive events (dessert, no dessert) appear in the columns. The ends of the columns and rows should sum up. (as seen in the example, where 75+25 = 100)

Your result with the venn diagram approach does not give the answer, since you assumed that 25% only drink coffee. But those 25% do not represent the people who 'did not have dessert' ( If they didn't have dessert it does not mean that they had only coffee, what if they didn't have anything?).

I've attached a word file with an explanation. Hope it helps!

abhi47 wrote:

If 75 percent of the guests at a certain banquet ordered dessert, what percent of the guests ordered coffee ?

1) 60 percent of the guests who ordered dessert also ordered coffee.

2)90 percent of the guests who ordered coffee also ordered dessert.

In the book it is solved using venn diagrams. Could someone explain how this problem can be solved using the two set matrix ?

The matrix approach is a convenient and structured way of using venn diagrams when there are 2 elements involved. The 2 mutually exclusive events ( coffee, no coffee) appear in rows, and 2 mutually exclusive events (dessert, no dessert) appear in the columns. The ends of the columns and rows should sum up. (as seen in the example, where 75+25 = 100)

Your result with the venn diagram approach does not give the answer, since you assumed that 25% only drink coffee. But those 25% do not represent the people who 'did not have dessert' ( If they didn't have dessert it does not mean that they had only coffee, what if they didn't have anything?).

I've attached a word file with an explanation. Hope it helps!

abhi47 wrote:

If 75 percent of the guests at a certain banquet ordered dessert, what percent of the guests ordered coffee ?

1) 60 percent of the guests who ordered dessert also ordered coffee.

2)90 percent of the guests who ordered coffee also ordered dessert.

In the book it is solved using venn diagrams. Could someone explain how this problem can be solved using the two set matrix ?

Thanks in advance.

I dindt assumed that 25% drink coffe, I just took a sample space of 100 out of which 75% was given that they eat dessert and out of these 60%(75%) both, so 25 automatically comes out, as 60% of 75%(= 75 as we have chosen a sample space of 100) so only who eat dessert are 75-45 = 30

30 + 45 + C = 100 c=25, it didnt assumd it comes out to be...

Re: If 75 percent of the guests at a certain banquet ordered des [#permalink]
23 Sep 2013, 00:48

Expert's post

If 75% of guest at a certain banquet ordered dessert, what percent of guest ordered coffee?

Assume there were 100 guests on the banquet. So we have that 75 of them ordered dessert.

(1) 60% of the guest who ordered dessert also ordered coffee --> 0.45*75=45 guests ordered both dessert AND coffee, but we still don't know how many guests ordered coffee. Not sufficient.

(2) 90% of the guest who ordered coffee also ordered dessert --> 0.9*(coffee) # of guests who ordered both dessert AND coffee. Not sufficient.

(1)+(2) From (1) # of guests who ordered both dessert AND coffee is 45 and from (2) 0.9*(coffee)=45 --> (coffee)=50. Sufficient.

Type of Visa: You will be applying for a Non-Immigrant F-1 (Student) US Visa. Applying for a Visa: Create an account on: https://cgifederal.secure.force.com/?language=Englishcountry=India Complete...

I started running back in 2005. I finally conquered what seemed impossible. Not sure when I would be able to do full marathon, but this will do for now...