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Re: If 75 percent of the guests at a certain banquet ordered dessert, what [#permalink]
16 Aug 2010, 12:33
From 2 , c/x = 25, doesn't make sense... Perhaps we are assuming that each ordered D or C. That is perhaps an incorrect assumption... In which case, we will need both the equations to solve for C and X
X = .75X + C - 0.6 x 0.75X + N X = 0.75X + C - 0.9C + N
Re: If 75 percent of the guests at a certain banquet ordered dessert, what [#permalink]
29 Dec 2015, 21:08
1
This post received KUDOS
Expert's post
metallicafan wrote:
If 75 percent of the guests at a certain banquet ordered dessert, what percent of the guests ordered coffee?
(1) 60 percent of the guests who ordered dessert also ordered coffee. (2) 90 percent of the guests who ordered coffee also ordered dessert.
If 75 percent of the guests at a certain banquet ordered dessert, what percent of the guests ordered coffee?
Assume there were 100 guests on the banquet. So we have that 75 of them ordered dessert.
(1) 60 percent of the guests who ordered dessert also ordered coffee --> 0.6*75=45 guests ordered both dessert AND coffee, but we still don't know how many guests ordered coffee. Not sufficient.
(2) 90 percent of the guests who ordered coffee also ordered dessert --> 0.9*(coffee) # of guests who ordered both dessert AND coffee. Not sufficient.
(1)+(2) From (1) # of guests who ordered both dessert AND coffee is 45 and from (2) 0.9*(coffee)=45 --> (coffee)=50. Sufficient.
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