Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Statement 1) Sure, we know that if 0 < b < 1, then a has to be a fraction (or decimal), like b = 1/4 so A = 1/2 OR -1/2. In the case where a = -1/2, it is not between 0 and 1. INSUFFICIENT.

Statement 2) Tells us the same thing as Statement 1 but in a different way. Insufficient.

Together) Insufficient becuase we're told the same thing with each statement but in different ways. No information we are given tells us if A must be positive or negative.

sachinn wrote:

If a^2 = b, is the value of a between 0 and 1.

1) b is between 0 and 1. 2) a> b

_________________

------------------------------------ J Allen Morris **I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

I wasn't thinking about b being positive (essentially b = |a|^2, so the answer will never be negative) and if a > b then we know a must be positive. In an indirect way, it tells us that a is indeed positive.

Nice catch fresinha. +1

fresinha12 wrote:

sachinn wrote:

If a^2 = b, is the value of a between 0 and 1.

1) b is between 0 and 1. 2) a> b

a^2=+ ..so B is positive..

OK..now if a>b...then sqrt(b)=a..

here we know that sqrt(b) is positive..thus a has to be positive..therefore sufficient

B it is..

_________________

------------------------------------ J Allen Morris **I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

1) alone is NOT Sufficient. Same reason as in my last message.

2) alone is sufficient. Because a^2 = b, so b > 0 (also because a > b, b should be be 0) as b > 0, and a > b, then a > 0 a > b = a^2 a > a^2 so a must be less than 1 combine all, 0 < a < 1