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If a and b are consecutive negative integers, is a less than

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If a and b are consecutive negative integers, is a less than [#permalink] New post 07 Jun 2010, 15:17
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If a and b are consecutive negative integers, is a less than b ?

(1) a + 1 and b - 1 are consecutive negative integers.
(2) a is an odd integer.
[Reveal] Spoiler: OA
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Re: Consecutive integers- 600 level question [#permalink] New post 08 Jun 2010, 06:00
Expert's post
shekar123 wrote:
If a and b are consecutive negative integers, is a less than b ?

(1) a + 1 and b - 1 are consecutive negative integers.
(2) a is an odd integer.



a and b are consecutive integers means that either:
b=a+1 (for example a=-5 and b=-4), in this case a<b;
OR:
a=b+1 (for example a=-5 and b=-6), in this case a>b.

So the we should determine which case we have.

(1) a+1 and b-1are consecutive negative integers --> again either a+1=b-1+1 --> a+1=b (first case so a<b) or b-1=a+1+1 --> b=a+3, which is not possible as a and b are consecutive integers (difference between two consecutive integers can not equal to 3). Sufficient.

(2) a is an odd integer. Clearly insufficient.

Answer: A.
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Kudos [?]: 10 [0], given: 4

Re: Consecutive integers- 600 level question [#permalink] New post 08 Jun 2010, 20:23
Could you please tell me as to how did u get this

b-1=a+1+1 --> b=a+3

Thanks

Bunuel wrote:
shekar123 wrote:
If a and b are consecutive negative integers, is a less than b ?

(1) a + 1 and b - 1 are consecutive negative integers.
(2) a is an odd integer.



a and b are consecutive integers means that either:
b=a+1 (for example a=-5 and b=-4), in this case a<b;
OR:
a=b+1 (for example a=-5 and b=-6), in this case a>b.

So the we should determine which case we have.

(1) a+1 and b-1are consecutive negative integers --> again either a+1=b-1+1 --> a+1=b (first case so a<b) or b-1=a+1+1 --> b=a+3, which is not possible as a and b are consecutive integers (difference between two consecutive integers can not equal to 3). Sufficient.

(2) a is an odd integer. Clearly insufficient.

Answer: A.
Expert Post
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Joined: 02 Sep 2009
Posts: 19041
Followers: 3366

Kudos [?]: 24478 [0], given: 2680

Re: Consecutive integers- 600 level question [#permalink] New post 09 Jun 2010, 03:51
Expert's post
shekar123 wrote:
Could you please tell me as to how did u get this

b-1=a+1+1 --> b=a+3

Thanks


Simple math:
b-1 and a+1 are consecutive integers --> (b-1)=(a+1)+1 --> b-1=a+2 --> add 1 to both sides --> b-1+1=a+2+1 --> b=a+3.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: Consecutive integers- 600 level question   [#permalink] 09 Jun 2010, 03:51
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