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Re: How to solve quickly!?!? [#permalink]
17 Mar 2011, 12:28

There is no sign in (2) so i could not sell anything about it.

Regarding (1): It is obviously not enough. Assume that b is 0 and a is -1. Then the inequality is 0<-1 which is false Assume that b is -1 and a is -2. Then the inequality is -2<-1 which is true _________________

If my post is useful for you not be ashamed to KUDO me! Let kudo each other!

Re: How to solve quickly!?!? [#permalink]
17 Mar 2011, 18:00

You dont need to know the sign dood. You have the official answer, which is E.

Therefore the sign must have been ab <0.

(If it was ab>0 then we would know that both a and b are positive integers. This would be enough information to know that the above inequality is always incorrect).

Therefore we know that a is +ve integer, b is -ve integer. Unfortunately this information does not let us solve it, and to solve this quickly we just plug in numbers.

A=5, B=-2.... 10>7 A=5, B=-1.....5<6. We dont know from both so E, quickly move on.

Re: How to solve quickly!?!? [#permalink]
17 Mar 2011, 22:06

Yeah subhash, I misread (1) as saying that a is +ve, hence everything I wrote is for that case.. (why I always get a couple questions wrong in Q =/)

If we take ab>=0 as per the link, and a<0, then a is -ve, b is 0 or -ve.

choose a=-5. is -5 |b|<-5-b ??? For any neg integer b, RHS will at least be -4 while LHS will at most be -5. Therefore it would be (C).. only b can be 0! In that case it doesnt stand, 0 is not <a (as per statement 1), so the possibility of b=0 makes it (E).

Last edited by bostonrb on 18 Mar 2011, 04:06, edited 1 time in total.