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There is no sign in (2) so i could not sell anything about it.

Regarding (1): It is obviously not enough. Assume that b is 0 and a is -1. Then the inequality is 0<-1 which is false Assume that b is -1 and a is -2. Then the inequality is -2<-1 which is true _________________

If my post is useful for you not be ashamed to KUDO me! Let kudo each other!

You dont need to know the sign dood. You have the official answer, which is E.

Therefore the sign must have been ab <0.

(If it was ab>0 then we would know that both a and b are positive integers. This would be enough information to know that the above inequality is always incorrect).

Therefore we know that a is +ve integer, b is -ve integer. Unfortunately this information does not let us solve it, and to solve this quickly we just plug in numbers.

A=5, B=-2.... 10>7 A=5, B=-1.....5<6. We dont know from both so E, quickly move on.

Yeah subhash, I misread (1) as saying that a is +ve, hence everything I wrote is for that case.. (why I always get a couple questions wrong in Q =/)

If we take ab>=0 as per the link, and a<0, then a is -ve, b is 0 or -ve.

choose a=-5. is -5 |b|<-5-b ??? For any neg integer b, RHS will at least be -4 while LHS will at most be -5. Therefore it would be (C).. only b can be 0! In that case it doesnt stand, 0 is not <a (as per statement 1), so the possibility of b=0 makes it (E).

Last edited by bostonrb on 18 Mar 2011, 05:06, edited 1 time in total.

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