If a and b are integers, and |a| > |b|, is a |b| < a

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If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

06 Apr 2008, 08:13

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If a and b are integers, and |a| > |b|, is a · |b| < a – b?

(1) a < 0

(2) ab >= 0
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Re: DS: abs value [#permalink]

06 Apr 2008, 10:31

if this question is from CB its gotta be a trick question...
hmm

I get E..

if a<0 then

say if a=-10
b=1
-10<-10-1; -10>-11
if b=-1
-10<-9
insuff

if ab>=0
well if a=6 and b=0
0<6
if a=-6 then 0>-6
insuff
together

OK so we know both a and b are <0

suppose a=-2 b=-1
-2<-1

a=-10 b=-1
-10<-9

but we dont know if B=0 or not

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Re: DS: abs value [#permalink]

06 Apr 2008, 10:35

E.
st) while for most # it holds, it doesn't if b=0. InSUFF.
st2)ex: if a,b=positive then NO but if a,b=negative then YES. InSUFF.
C) if a<0 then b=<0. Again if a,b=negative then YES. but b=0 ruins.

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Re: DS: abs value [#permalink]

06 Apr 2008, 10:42

Quote:

OK so we know both a and b are <0

how do we know the above

we know that |a| > |b| and ab >= 0, which means b can be 0.

so lets try these values first
a=-2 , b= 0

a|b| = 0, a - b = -2 therefore a|b| > a-b

now lets try these
a=-2, b=-1
a|b| = -2 , a-b= -1 therefore a|b| < a-b

so I think this is E.

Re: DS: abs value [#permalink] 06 Apr 2008, 10:42

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If a and b are integers, and |a| > |b|, is a |b| < a

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If a and b are integers, and |a| > |b|, is a |b| < a

If a and b are integers, and |a| > |b|, is a |b| < a

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