Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 26 Apr 2015, 01:52

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If a and b are integers, and |a| > |b|, is a |b| < a

Author Message
TAGS:
Manager
Joined: 28 Jul 2004
Posts: 136
Location: Melbourne
Schools: Yale SOM, Tuck, Ross, IESE, HEC, Johnson, Booth
Followers: 1

Kudos [?]: 21 [0], given: 2

If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]  08 Nov 2008, 04:49
If a and b are integers, and |a| > |b|, is a · |b| < a – b?

(1) a < 0

(2) ab >= 0
_________________

kris

Intern
Joined: 07 Nov 2008
Posts: 32
Followers: 0

Kudos [?]: 6 [0], given: 0

Re: Modulus problem [#permalink]  08 Nov 2008, 05:12
If a and b are integers, and |a| > |b|, is a · |b| < a – b?

(1) a < 0 ,---> for example, if a=-2 and b=1, or a=-2 and b=-1,---> not suff

(2) ab >= 0 ---> if a=2 and b=0, or a=-2 and b= -1, ---> not suff

together, still not suff, for example, if a=-1 and b=-0.5, or a=-2 and b=-0.5

E
VP
Joined: 05 Jul 2008
Posts: 1433
Followers: 35

Kudos [?]: 254 [0], given: 1

Re: Modulus problem [#permalink]  08 Nov 2008, 09:28
Sion wrote:
If a and b are integers, and |a| > |b|, is a · |b| < a – b?

(1) a < 0 ,---> for example, if a=-2 and b=1, or a=-2 and b=-1,---> not suff

(2) ab >= 0 ---> if a=2 and b=0, or a=-2 and b= -1, ---> not suff

together, still not suff, for example, if a=-1 and b=-0.5, or a=-2 and b=-0.5

E

a & b are integers.

|a| > |b|

(1) a -ve , b can be +ve or -ve but the value with out sign must be less than than a.

a=-5 b =4 -20 < -9 Yes

a= -2 b =-1 -2 < -1 No

Insuff

(2) ab>=0 means

a or b both +ve or -ve or one of them zero. b is zero and a cannot be zero as |a| > |b|

a=4 b=3 12 < 1 N

a= -4 b =-3 -12 < -1 Y

Insuff

Together.

ab >=0 , a<0 , |a| > |b| means

a, b both -ve or b is zero and a cannot be zero as |a| > |b|

a= -4 b =-3 -12 < -1 Y

a =-4 b =0 0 < -4 N

Still Insuff

E
Re: Modulus problem   [#permalink] 08 Nov 2008, 09:28
Similar topics Replies Last post
Similar
Topics:
If a and b are integers, and |a| > |b|, is a |b| < a 6 29 Jun 2008, 21:09
If a and b are integers, and |a| > |b|, is a |b| < a 3 06 Apr 2008, 07:13
If a and b are integers, and |a| > |b|, is a |b| < a 2 24 Jun 2007, 15:28
1 If a and b are integers, and |a| > |b|, is a |b| < a 13 26 Dec 2006, 18:36
If a and b are integers, and |a| > |b|, is a |b| < a 1 22 Nov 2006, 12:25
Display posts from previous: Sort by