Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 26 Apr 2015, 13:10

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

If a and b are integers, and |a| > |b|, is a |b| < a

 Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:
Manager
Joined: 09 Jul 2008
Posts: 111
Location: Dallas, TX
Schools: McCombs 2011
Followers: 1

Kudos [?]: 10 [0], given: 1

If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]  04 Jan 2009, 18:17
If a and b are integers, and |a| > |b|, is a · |b| < a – b?

(1) a < 0

(2) ab >= 0

Interested in seeing efficient approach for this. My approach of trying every combination takes way too long. Thanks!
Intern
Joined: 30 Sep 2008
Posts: 37
Followers: 0

Kudos [?]: 1 [0], given: 1

Re: Absolutes and Inequality confusion [#permalink]  04 Jan 2009, 20:02
Is it the OA is E ?

I tried the no. also but when see the problem like this
I usaully assume that the no. in absolute is zero
Manager
Joined: 09 Jul 2008
Posts: 111
Location: Dallas, TX
Schools: McCombs 2011
Followers: 1

Kudos [?]: 10 [0], given: 1

Re: Absolutes and Inequality confusion [#permalink]  04 Jan 2009, 20:31
GMATpp wrote:
Is it the OA is E ?

I tried the no. also but when see the problem like this
I usaully assume that the no. in absolute is zero

Not sure if I understand your method.. Can you elaborate. Do you assume a and b = 0 ??
Intern
Joined: 30 Sep 2008
Posts: 37
Followers: 0

Kudos [?]: 1 [0], given: 1

Re: Absolutes and Inequality confusion [#permalink]  04 Jan 2009, 21:34
I assume B = 0 according to l a l > l b l
so it would be easy to think about value of a.

then try the numbers
SVP
Joined: 17 Jun 2008
Posts: 1573
Followers: 12

Kudos [?]: 202 [0], given: 0

Re: Absolutes and Inequality confusion [#permalink]  04 Jan 2009, 22:06
I also got E with the following approach:

From the question |a| > |b| or, a^2 > b^2
or, (a-b)(a+b) > 0 and this means, either a > b and a > -b or, a < b and a < -b

Now, a > b and a > -b is possible only if a and b are both positive
and a < b and a < -b is possible only if a < 0.

Now, if a > 0 then a.|b| > 0 and a-b > 0 but, a.|b| < a-b may not be true.
Similarly, if a < 0 then both a.|b| and a-b will be < 0 but again, inequality may not be true.

Now stmt1 does not give any extra information. Insufficient.
Stmt2 also does not give any extra information. Insufficient.
Intern
Joined: 19 Jun 2008
Posts: 20
Followers: 0

Kudos [?]: 15 [0], given: 0

Re: Absolutes and Inequality confusion [#permalink]  07 Jan 2009, 10:36
scthakur wrote:
I also got E with the following approach:

From the question |a| > |b| or, a^2 > b^2
or, (a-b)(a+b) > 0 and this means, either a > b and a > -b or, a < b and a < -b

Now, a > b and a > -b is possible only if a and b are both positive
and a < b and a < -b is possible only if a < 0.

Now, if a > 0 then a.|b| > 0 and a-b > 0 but, a.|b| < a-b may not be true.
Similarly, if a < 0 then both a.|b| and a-b will be < 0 but again, inequality may not be true.

Now stmt1 does not give any extra information. Insufficient.
Stmt2 also does not give any extra information. Insufficient.

When you say that a > b and a > -b is possible only if a and b are both positive, does that mean in all cases or only in some? If a =2 and b =-1 it holds true as well.
Re: Absolutes and Inequality confusion   [#permalink] 07 Jan 2009, 10:36
Similar topics Replies Last post
Similar
Topics:
If a and b are integers, and |a| > |b|, is a |b| < a 6 29 Jun 2008, 21:09
If a and b are integers, and |a| > |b|, is a |b| < a 3 06 Apr 2008, 07:13
If a and b are integers, and |a| > |b|, is a |b| < a 2 24 Jun 2007, 15:28
1 If a and b are integers, and |a| > |b|, is a |b| < a 13 26 Dec 2006, 18:36
If a and b are integers, and |a| > |b|, is a |b| < a 1 22 Nov 2006, 12:25
Display posts from previous: Sort by

If a and b are integers, and |a| > |b|, is a |b| < a

 Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.