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If a and b are integers, and |a| > |b|, is a |b| < a

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Re: If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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New post 13 Mar 2016, 00:52
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Re: If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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New post 06 May 2016, 03:09
Raths wrote:
is a - |b| < a - b
canceling a from both sides , the eqn becomes |b| > b
so basically the eqn is asking if b is -ve or not . Therefore , we will check for that

1 . a < 0 , does not talk about b
2. ab >= 0 implies a>=0 and b>=0
or a<=0 and b<=0

therefore not sufficient

combining both we get b<=0 which is also not sufficient since b=0 does not satisfy the
main question . I hope doing this way you feel faster.
Also I think that the condition |a| > |b| is irrelevant to the question.


Can anyone tell me if this is a correct method or not?
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If a and b are integers, and |a| > |b|, is a - |b| < a – b? [#permalink]

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New post 06 May 2016, 08:50
If a and b are integers, and |a| > |b|, is a - |b| < a – b?

(1) a < 0

(2) ab >= 0
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Re: If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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New post 06 May 2016, 09:16
Expert's post
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Re: If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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New post 06 May 2016, 09:26
Thanks Bunnel. Sorry, I missed this discussion. Should I delete my other post?
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Re: If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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New post 06 May 2016, 09:28
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If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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New post 09 May 2016, 23:25
I personally am always prefer the algebraic method to solve rather than mumber plugin. I came up with this way to solve. Please comment if it is acceptable or not.
Attachments

IMG-20160510-WA0001.jpg
IMG-20160510-WA0001.jpg [ 115.68 KiB | Viewed 94 times ]

File comment: I have not solved for the second statement and also combining both the statements because they are the subset as computed for the statement 1.

So the answer ie E

IMG-20160510-WA0003.jpg
IMG-20160510-WA0003.jpg [ 139.11 KiB | Viewed 94 times ]

If a and b are integers, and |a| > |b|, is a |b| < a   [#permalink] 09 May 2016, 23:25

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If a and b are integers, and |a| > |b|, is a |b| < a n2739178 6 17 Mar 2011, 10:49
1 Experts publish their posts in the topic If a and b are integers, and |a| > |b|, is a |b| < a Orange08 6 19 Sep 2010, 13:21
6 Experts publish their posts in the topic If a and b are integers, and |a| > |b|, is a |b| < a yangsta8 18 10 Oct 2009, 06:51
6 Experts publish their posts in the topic If a and b are integers, and |a| > |b|, is a |b| < a anindyat 14 26 Dec 2006, 19:36
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If a and b are integers, and |a| > |b|, is a |b| < a

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