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Re: If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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12 Mar 2016, 23:52

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Re: If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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06 May 2016, 02:09

Raths wrote:

is a - |b| < a - b canceling a from both sides , the eqn becomes |b| > b so basically the eqn is asking if b is -ve or not . Therefore , we will check for that

1 . a < 0 , does not talk about b 2. ab >= 0 implies a>=0 and b>=0 or a<=0 and b<=0

therefore not sufficient

combining both we get b<=0 which is also not sufficient since b=0 does not satisfy the main question . I hope doing this way you feel faster. Also I think that the condition |a| > |b| is irrelevant to the question.

Can anyone tell me if this is a correct method or not?

Re: If a and b are integers, and |a| > |b|, is a |b| < a [#permalink]

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09 May 2016, 22:25

I personally am always prefer the algebraic method to solve rather than mumber plugin. I came up with this way to solve. Please comment if it is acceptable or not.

Attachments

IMG-20160510-WA0001.jpg [ 115.68 KiB | Viewed 265 times ]

File comment: I have not solved for the second statement and also combining both the statements because they are the subset as computed for the statement 1.

So the answer ie E

IMG-20160510-WA0003.jpg [ 139.11 KiB | Viewed 265 times ]

gmatclubot

Re: If a and b are integers, and |a| > |b|, is a |b| < a
[#permalink]
09 May 2016, 22:25

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