Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Guys, you have to write the question stem correctly. Use brackets!

[(4^A)*((1/3)^B)]<1 now all is clear

(1) A=2B; thus, (16^B)*(1/3^B)=(16/3)^B if B=1, then it is >1, if B=-3000, then it is <1
(2) B=4 we have nothing on A, so it is not enough. Consider A=1000 and A=-1000.

Combine: (16/3)^4>1, which is OK. Thus, it is C.
The problem seems so simple...

Re: GMAT-DS: a and b [#permalink]
21 Feb 2008, 13:32

in the question, notwithstanding the correction, there is an explicit statement of A and B being positive integers. if so, then (16/3)^b is always greater than 1. Hence (i) is sufficient. however, for (ii), you end up with 2^{2a}/81; where for a < 7, the given statement is true. while for a > 6, this isn't. so (ii) is insufficient.

Re: GMAT-DS: a and b [#permalink]
23 Feb 2008, 19:33

kanyshkae wrote:

in the question, notwithstanding the correction, there is an explicit statement of A and B being positive integers. if so, then (16/3)^b is always greater than 1. Hence (i) is sufficient. however, for (ii), you end up with 2^{2a}/81; where for a < 7, the given statement is true. while for a > 6, this isn't. so (ii) is insufficient.

Hence A.

yep. has to be A. _________________

-Underline your question. It takes only a few seconds! -Search before you post.

gmatclubot

Re: GMAT-DS: a and b
[#permalink]
23 Feb 2008, 19:33

I am not panicking. Nope, Not at all. But I am beginning to wonder what I was thinking when I decided to work full-time and plan my cross-continent relocation...

Over the last week my Facebook wall has been flooded with most positive, almost euphoric emotions: “End of a fantastic school year”, “What a life-changing year it’s been”, “My...