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# IF a and b are positive integers, is < 1? 1) b = 2a

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Manager
Joined: 28 Feb 2003
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IF a and b are positive integers, is < 1? 1) b = 2a [#permalink]  14 Jun 2003, 19:59
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IF a and b are positive integers, is [4^a*(1/3)^b] < 1?

1) b = 2a............
2) b = 4

Last edited by brstorewala on 16 Jun 2003, 05:15, edited 1 time in total.
Manager
Joined: 28 Feb 2003
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I agree with A, but the official answer says C???????????
SVP
Joined: 03 Feb 2003
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Guys, you have to write the question stem correctly. Use brackets!

[(4^A)*((1/3)^B)]<1 now all is clear

(1) A=2B; thus, (16^B)*(1/3^B)=(16/3)^B if B=1, then it is >1, if B=-3000, then it is <1
(2) B=4 we have nothing on A, so it is not enough. Consider A=1000 and A=-1000.

Combine: (16/3)^4>1, which is OK. Thus, it is C.
The problem seems so simple...
Manager
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Sorry guys......i screwed up again.....made a typo in statement 1, now i have corrected it.....please answer again.....sorry again

this test is getting on my nervesssss
Manager
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Ans : A (for b=2a)

for all positive integers of a and b the equation is always < 1, thus the ans is a definitely YES

for a=2b then the ans would always be NO , thus still sufficient. and Ans is A.
Intern
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Re: GMAT-DS: a and b [#permalink]  21 Feb 2008, 13:32
in the question, notwithstanding the correction, there is an explicit statement of A and B being positive integers. if so, then (16/3)^b is always greater than 1. Hence (i) is sufficient.
however, for (ii), you end up with 2^{2a}/81; where for a < 7, the given statement is true. while for a > 6, this isn't. so (ii) is insufficient.

Hence A.
Senior Manager
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Re: GMAT-DS: a and b [#permalink]  23 Feb 2008, 19:33
kanyshkae wrote:
in the question, notwithstanding the correction, there is an explicit statement of A and B being positive integers. if so, then (16/3)^b is always greater than 1. Hence (i) is sufficient.
however, for (ii), you end up with 2^{2a}/81; where for a < 7, the given statement is true. while for a > 6, this isn't. so (ii) is insufficient.

Hence A.

yep. has to be A.
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Re: GMAT-DS: a and b   [#permalink] 23 Feb 2008, 19:33
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