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# If a and b are two different integers (positive or negative)

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Senior Manager
Joined: 20 Feb 2007
Posts: 257
Followers: 1

Kudos [?]: 13 [0], given: 0

If a and b are two different integers (positive or negative) [#permalink]  16 Mar 2007, 18:11
If a and b are two different integers (positive or negative) and a is not equal to -b, is |a-b| > 1 or |b-a| > 1 always?

Director
Joined: 13 Dec 2006
Posts: 521
Location: Indonesia
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Kudos [?]: 104 [0], given: 0

no its not always true

explanation.

Assume that both a and b are positive and a= b (though a is not equal to -b but can be equal to b) so !a-b! = 0, which is less than 1. also for the value of a = 2 and b = 3 the eq is not great than 1.

hence its not always true

regards,

Senior Manager
Joined: 20 Feb 2007
Posts: 257
Followers: 1

Kudos [?]: 13 [0], given: 0

If a and b are two different integers (positive or negative) and a is not equal to b or -b, is |a-b| > 1 or |b-a| > 1 always?

Director
Joined: 13 Dec 2006
Posts: 521
Location: Indonesia
Followers: 6

Kudos [?]: 104 [0], given: 0

Hi,

In that case also it wont be always true read my answer which says if a=2 and b=3 then !a-b! or !b-a! will be = 1 and not greater than 1.

regards,

Amardeep
SVP
Joined: 01 May 2006
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Just one more thing

|a-b| = |(-1)*(b-a)| = |-1| * |b-a| = 1 * |b-a| = |b-a|

So, to consider |a-b| > 1, we consider |b-a| > 1
Senior Manager
Joined: 20 Feb 2007
Posts: 257
Followers: 1

Kudos [?]: 13 [0], given: 0

Thanks Amardeep and Fig!
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