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2) b + c + d = 300 -------> c + d = 300 - b a + b > c + d 200 > 300-b 300-b is \((-\infty,200)\) ------->\(300 - (100,+\infty)=(-\infty,200)\) 200 > 300-b is true -------> a + b > c + d is true sufficient. _________________

Hi walker, I am still lost on how statement two is sufficient.

Any other way to explain it?

walker wrote:

2) b + c + d = 300 -------> c + d = 300 - b a + b > c + d 200 > 300-b 300-b is \((-\infty,200)\) ------->\(300 - (100,+\infty)=(-\infty,200)\) 200 > 300-b is true -------> a + b > c + d is true sufficient.

from the stem a+b = 200 and a<b therefore b>100 and a<100

so lets take b a little more than 100, eg 101 for arguments sake

now lets plug it into the second piece of data.

c + d = 300 - b = 300 - 101 = 199

therefore c + d < 200, sufficient

AVakil wrote:

Hi walker, I am still lost on how statement two is sufficient.

Any other way to explain it?

walker wrote:

2) b + c + d = 300 -------> c + d = 300 - b a + b > c + d 200 > 300-b 300-b is \((-\infty,200)\) ------->\(300 - (100,+\infty)=(-\infty,200)\) 200 > 300-b is true -------> a + b > c + d is true sufficient.

2: c+d=300-b 200>300-b --> -100>-b ---> 100<b? Yes b/c a<b and a+b=200. Thus B>=101 (assuming a and b are integers, we could have b=100.000000000000001 etc...) Either way B>100 so 2 is suff.

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