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If a, b, and c are consecutive integers and a < b < c, [#permalink]
17 Oct 2005, 12:40

If a, b, and c are consecutive integers and a < b < c, which of the following must be true?
I. b - c = 1
II. abc/3 is an integer.
III. a + b + c is even

0 is not an integer. So you cannot consider it in a sequence.

i) if a,b,c -> -10,-11,-12, then b-c=-1. Not true
ii) abc/3 - Since there is atleast one odd number in the seq., abc should be divisible by 3. True
iii) a+b+c cannnot be even if there are 2 even numbers in the seq. Not true

0 is not an integer. So you cannot consider it in a sequence.

i) if a,b,c -> -10,-11,-12, then b-c=-1. Not true ii) abc/3 - Since there is atleast one odd number in the seq., abc should be divisible by 3. True iii) a+b+c cannnot be even if there are 2 even numbers in the seq. Not true

gsr: 0 is very much an integer! Else why would you have it on a number line!! However, zero is neither positive nor negative.
In any case II still holds... 0 divided by any number is 0 which is an integer. _________________

0 is not an integer. So you cannot consider it in a sequence.

i) if a,b,c -> -10,-11,-12, then b-c=-1. Not true ii) abc/3 - Since there is atleast one odd number in the seq., abc should be divisible by 3. True iii) a+b+c cannnot be even if there are 2 even numbers in the seq. Not true

gsr: 0 is very much an integer! Else why would you have it on a number line!! However, zero is neither positive nor negative. In any case II still holds... 0 divided by any number is 0 which is an integer.

I am sorry. You are right!
I was thinking of something else and in the end confused everyone!!

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