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# If a, b, and c are consecutive integers, where a<b<c,

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Current Student
Joined: 11 May 2008
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If a, b, and c are consecutive integers, where a<b<c, [#permalink]

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22 Jul 2008, 01:42
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If a, b, and c are consecutive integers, where a<b<c, which of the following cannot be the value of c^2-(a^2+b^2)?
(A) -77
(B) -32
(C) -21
(D) -10
(E) 0
Director
Joined: 27 May 2008
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22 Jul 2008, 01:58
D -10.

a = b-1
b = b
c = b+1

(b+1)^2 - (b-1)^2 - b^2
=4b-b^2
=b(4-b)

factors of -10 will never have a difference of 4..
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Joined: 22 Mar 2008
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22 Jul 2008, 20:28
ans is D) for same reason above
Re: CONSECUTIVE INTEGERS   [#permalink] 22 Jul 2008, 20:28
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