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If a, b, and c are consecutive integers, where a<b<c, [#permalink]
 22 Jul 2008, 02:42
If a, b, and c are consecutive integers, where a<b<c, which of the following cannot be the value of c^2-(a^2+b^2)?
(A) -77
(B) -32
(C) -21
(D) -10
(E) 0
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Re: CONSECUTIVE INTEGERS [#permalink]
22 Jul 2008, 02:58
D -10.
a = b-1
b = b
c = b+1
(b+1)^2 - (b-1)^2 - b^2
=4b-b^2
=b(4-b)
factors of -10 will never have a difference of 4..
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Re: CONSECUTIVE INTEGERS [#permalink]
22 Jul 2008, 21:28
ans is D) for same reason above
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Re: CONSECUTIVE INTEGERS
[#permalink]
22 Jul 2008, 21:28
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