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If a, b, and c are consecutive positive even integers and a [#permalink]
 06 Feb 2008, 08:40
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If a, b, and c are consecutive positive even integers and a > b > c,
which of the following could be equal to a - b - c ?
A) 6
(B) 2
(C) -1
(D) -3
(E) -4
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Director
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lumone wrote: If a, b, and c are consecutive positive even integers and a > b > c,
which of the following could be equal to a - b - c ?
A) 6
(B) 2
(C) -1
(D) -3
(E) -4 a = 2n (n>=3), b = 2n - 2, c = 2n - 4 a -b -c = 2n - (2n-2) - (2n-4) = 6 - 2n <= 0 since n >=3 , even -> E
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maratikus wrote: lumone wrote: If a, b, and c are consecutive positive even integers and a > b > c,
which of the following could be equal to a - b - c ?
A) 6
(B) 2
(C) -1
(D) -3
(E) -4 a = 2n (n>=3), b = 2n - 2, c = 2n - 4 a -b -c = 2n - (2n-2) - (2n-4) = 6 - 2n <= 0 since n >=3 , even -> E i have no idea what you did but i shifted the chain until it reached 10 8 6 and got E 
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Manager
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maratikus,
a = 2n (n>=3), b = 2n - 2, c = 2n - 4
Why cant it be n>=2
If n =2 we get
a = 4 b= 2 c = 0
Not sure where I am going wrong?
-Jack
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Director
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jackychamp wrote: maratikus,
a = 2n (n>=3), b = 2n - 2, c = 2n - 4
Why cant it be n>=2
If n =2 we get
a = 4 b= 2 c = 0
Not sure where I am going wrong?
-Jack a,b,c - consecutive POSITIVE even integers, 0 is not a positive integer
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Director
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bmwhype2 wrote: i have no idea what you did but i shifted the chain until it reached 10 8 6 and got E I have no idea why you shifted the chain to 10 8 6 but both of us solved the problem correctly.
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Director
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lumone wrote: If a, b, and c are consecutive positive even integers and a > b > c,
which of the following could be equal to a - b - c ?
A) 6
(B) 2
(C) -1
(D) -3
(E) -4 a-b = 2 therefore 2-c = x also note since even-even-even = even eliminate c),d) if 2-c > 2 , c<= 0 hence x < 0 only E fits this, ans = e)
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Senior Manager
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maratikus wrote: bmwhype2 wrote: i have no idea what you did but i shifted the chain until it reached 10 8 6 and got E I have no idea why you shifted the chain to 10 8 6 but both of us solved the problem correctly. And I have no idea what you all did and still can't solve the problem.  Is anyone able to explain with more details?
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Manager
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lumone wrote: maratikus wrote: bmwhype2 wrote: i have no idea what you did but i shifted the chain until it reached 10 8 6 and got E I have no idea why you shifted the chain to 10 8 6 but both of us solved the problem correctly. And I have no idea what you all did and still can't solve the problem. Is anyone able to explain with more details? The long way is plugging in numbers for a > b > c, Remember they are consecutive positive even integers CBA could be 2,4,6 or 4, 6, 8 or 6, 8, 10 and so on. Then you plug into a - b - c. The first two sets of numbers aren't in the answers so this is why I say it's the LONG way. I would use the formula provided above by maratikus. It says A (the largest number) is 2N, then B would be 2N-2 (b/c it's consecutive even), Then that would make the smallest number C, 2N-4. Then you'd plug in ABC into formula as seen below. Hope this helps. a = 2n (n>=3), b = 2n - 2, c = 2n - 4
a -b -c = 2n - (2n-2) - (2n-4) = 6 - 2n <= 0 since n >=3 , even -> EIf a, b, and c are consecutive positive even integers and a > b > c, which of the following could be equal to a - b - c ? A) 6 (B) 2 (C) -1 (D) -3 (E) -4
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VP
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consectutive even , X , X + 2 , X + 4 where X = Even
now subtract X - (X+2) - (X+4)
doing this leaves us with -X + -2
what even number can we substitute in X to yield an answer choice
E works -4 (plug in 2 for X)
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