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# If a, b, and c are digits, is (a + b + c) a multiple of 8?

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Senior Manager
Joined: 04 Jan 2006
Posts: 280
Followers: 1

Kudos [?]: 18 [0], given: 0

If a, b, and c are digits, is (a + b + c) a multiple of 8? [#permalink]  01 Feb 2007, 17:14
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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 1 sessions
Q: If a, b, and c are digits, is (a + b + c) a multiple of 8?

(1) The three-digit number abc is a multiple of 8.
(2) a x b x c is a multiple of 8.

Note: I hate this kind of question. Does anyone have any tips to deal with it?
Senior Manager
Joined: 24 Oct 2006
Posts: 341
Followers: 1

Kudos [?]: 16 [0], given: 0

S1:
840=8*105
8+4+0=12<>n8

440=8*55
4+4+0=8=m8

so insuff

S2:
2*4*6=48=8*6
2+4+6=12<>r8

4*2*2=16=8*2
4+2+2=8

so insuff

Together:
888=8*111
8+8+8=n8
8*8*8=x8

168=8*21
1*6*8=y8
1+6+8<>z8

so insuff. E should be the ans

Crazy method unless you are able to pick nos. quickly?
any other method?
SVP
Joined: 05 Jul 2006
Posts: 1537
Followers: 5

Kudos [?]: 87 [0], given: 39

sumithra i second you on this method
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