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If a,b and c are integers. Is their product a*b*c=0?

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If a,b and c are integers. Is their product a*b*c=0? [#permalink] New post 29 Mar 2007, 16:14
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If a,b and c are integers. Is their product a*b*c=0?
a)a^2=2a
b)b/c=[(a+b)^2/(a^2+b^2+2*a*b)]-1
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 [#permalink] New post 29 Mar 2007, 16:45
B.

at least one of the three must equal 0 in order for their product to equal 0.

(1) a can be 2 or 0. INSUFF

(2) (a+b)^2 = (a^2+b^2+2*a*b) so cancel them out.
b/c = 1-1 = 0
therefore b = 0.
SUFF
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 [#permalink] New post 29 Mar 2007, 17:32
My answer is 'B'.

Statement 1 does not tell anything about B or C . So NOT SUFF

Statement 2 gives b=0 if c not = 0. Suff

:lol:
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 [#permalink] New post 30 Mar 2007, 08:37
I don't think you can cancel them out because the denominator has -1. So the answer is E
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 [#permalink] New post 30 Mar 2007, 08:51
nasayin wrote:
I don't think you can cancel them out because the denominator has -1. So the answer is E


We can cancel out because the -1 is out of the external brackets. Unless the posted question has some typographical error.
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 [#permalink] New post 30 Mar 2007, 09:44
ywilfred wrote:
nasayin wrote:
I don't think you can cancel them out because the denominator has -1. So the answer is E


We can cancel out because the -1 is out of the external brackets. Unless the posted question has some typographical error.



Oops, you're right. I made the typo when writing the equation out on a piece of paper.
  [#permalink] 30 Mar 2007, 09:44
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