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If a, b, and c are positive distinct integers, is (a/b)/c an [#permalink]
13 Jul 2010, 09:48
Question Stats:
47% (01:59) correct
52% (00:59) wrong based on 21 sessions
If a, b, and c are positive distinct integers, is (a/b)/c an integer? (1) c = 2 (2) a = b+c
Last edited by Bunuel on 08 Nov 2012, 03:18, edited 1 time in total.
Edited the question.
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A humble request: I think there is a separate section for GMAT Club tests. There you can find the already discussed questions too. Now coming to the problem. 1 is clearly insufficient. 2 is sufficient. No combination can be found in which (a/b)/c is an integer provided a= b + c & a, b, c are distinct.
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bibha wrote: If a, b, and c are positive distinct integers, is (a/b)/c an integer? 1. c=2 2. a = b+c First of all \frac{\frac{a}{b}}{c}=\frac{a}{bc}. So the question becomes is \frac{a}{bc}=integer true? (1) c=2 --> is \frac{a}{2b}=integer. Clearly insufficient. If a=1, then answer is NO, but if a=4 and b=1, then the answer is YES. (2) a=b+c --> \frac{a}{bc}=\frac{b+c}{bc}=\frac{b}{bc}+\frac{c}{bc}=\frac{1}{c}+\frac{1}{b}. As b and c are distinct integers then \frac{1}{c}+\frac{1}{b} won't be an integer. Sufficient. (Side note: if b and c were not distinct integers then \frac{1}{c}+\frac{1}{b} could be an integer in the following cases: b=c=1 and b=c=2). Answer: B. Hope it helps.
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Re: If a, b, and c are positive distinct integers, is (a/b)/c an [#permalink]
07 Nov 2012, 20:37
Bunuel,
Stupid question. But....
When I see the question: Is a/bc = Integer. My mind immediately multiplies the equation by bc on both sides and comes up with a new question...
Is a = (integer) (bc)
since both b and c are distinct integers and thus bc will be an integer, the question is asking if a = integer.
If this is accurate, then isn't option B a straightforward Yes? If A = B +C, then A is just an addition of two distinct integers, making A itself an integer, answering the original question.
Can you help point out where I went wrong?
Thanks.
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Re: If a, b, and c are positive distinct integers, is (a/b)/c an [#permalink]
08 Nov 2012, 03:27
navalpike wrote: Bunuel,
Stupid question. But....
When I see the question: Is a/bc = Integer. My mind immediately multiplies the equation by bc on both sides and comes up with a new question...
Is a = (integer) (bc)
since both b and c are distinct integers and thus bc will be an integer, the question is asking if a = integer.
If this is accurate, then isn't option B a straightforward Yes? If A = B +C, then A is just an addition of two distinct integers, making A itself an integer, answering the original question.
Can you help point out where I went wrong?
Thanks. If the question could be rephrased as "is a an integer", then we wouldn't need any statement to answer the question, since the stem directly says that a is an integer. The question asks whether \frac{a}{bc} is an integer or whether a is a multiple of bc. Hope it helps.
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COLLECTION OF QUESTIONS: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. NEW!!! ,11 Mixed Questions NEW!!!, 12 Fresh Meat NEW!!!
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Re: If a, b, and c are positive distinct integers, is (a/b)/c an
[#permalink]
08 Nov 2012, 03:27
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