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# If a>b>c>0, is c <3? (1) 1/a>1/3 (2) 1/a+1/b+1/c=1

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SVP
Joined: 05 Jul 2006
Posts: 1543
Followers: 4

Kudos [?]: 51 [0], given: 39

If a>b>c>0, is c <3? (1) 1/a>1/3 (2) 1/a+1/b+1/c=1 [#permalink]  15 Aug 2009, 23:45
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4)If a>b>c>0, is c <3?
(1) 1/a>1/3
(2) 1/a+1/b+1/c=1
Intern
Joined: 01 Aug 2009
Posts: 29
Location: Australia
Followers: 1

Kudos [?]: 13 [0], given: 3

Re: 4)If a>b>c>0, is c <3? [#permalink]  16 Aug 2009, 07:30
IMO....D

(1) 1/a>1/3
Solution: 0 < a < 3
Since a > b > c > 0....and a < 3, then c must be < 3.
Sufficient.

2) 1/a+1/b+1/c=1

1 = 1/3 + 1/3 + 1/3
if C=3 then 1/a < 1/b < 1/3
Hence, the sum of the fraction can never reach 1....

Therefore, c has to be < 3 in order to get the sum of fractions reach 1
Sufficient.
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CEO
Joined: 29 Aug 2007
Posts: 2504
Followers: 48

Kudos [?]: 451 [0], given: 19

Re: 4)If a>b>c>0, is c <3? [#permalink]  16 Aug 2009, 07:43
scarish wrote:
IMO....D

(1) 1/a>1/3
Solution: 0 < a < 3
Since a > b > c > 0....and a < 3, then c must be < 3.
Sufficient.

2) 1/a+1/b+1/c=1

1 = 1/3 + 1/3 + 1/3
if C=3 then 1/a < 1/b < 1/3
Hence, the sum of the fraction can never reach 1....

Therefore, c has to be < 3 in order to get the sum of fractions reach 1
Sufficient.

Thats D.
good job for good question.
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Director
Joined: 25 Oct 2008
Posts: 612
Location: Kolkata,India
Followers: 8

Kudos [?]: 117 [0], given: 100

Re: 4)If a>b>c>0, is c <3? [#permalink]  23 Oct 2009, 17:01
Stmt 2 is not crystal clear..

We have here,a+b+c=abc which is only true when a,b,c=3.However,from the stem we know that a>b>c..hmmm..getting there but missing something...
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Senior Manager
Joined: 16 Apr 2009
Posts: 342
Followers: 1

Kudos [?]: 37 [0], given: 14

Re: 4)If a>b>c>0, is c <3? [#permalink]  23 Oct 2009, 19:32
humm , for stmt 2 , is there any other way to solve the problem other than one mentioned by scarish

ab+bc+ab = abc , now can i solve from this ?
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Re: 4)If a>b>c>0, is c <3?   [#permalink] 23 Oct 2009, 19:32
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