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If a,b,c and d are positive integers, is (a/b) (c/d) > [#permalink]
 01 Aug 2010, 22:11
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If a,b,c and d are positive integers, is (a/b) (c/d) > c/b? A. c>b B. a>d Can someone explain?? OA is B
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Re: a,b,c and d inequality [#permalink]
02 Aug 2010, 00:01
Hi,
What is the operation between (a/b) and (c/d) in (a/b) (c/d) > c/b?
regards,
Jack
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Re: a,b,c and d inequality [#permalink]
02 Aug 2010, 00:34
Stmt 2 is sufficient as follows:
LHS and RHS can be rearranged into (a/d)(c/b) > (c/b)
As c and b are both positive (you don't need Stmt 1 for that), they can be cancelled out from both sides - which leaves us with a/d > 1 ??
Stmt 2 says exactly that. Hence sufficient.
Hope this helps.
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Re: a,b,c and d inequality [#permalink]
02 Aug 2010, 01:51
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(\frac{a}{b})(\frac{c}{d})=(\frac{a}{d})(\frac{c}{b})>(\frac{c}{b})Since a, b, c, d are positive, so both sides can be divided by (\frac{c}{b})\frac{(\frac{a}{d})(\frac{c}{b})}{(\frac{c}{b})}>\frac{(\frac{c}{b})}{(\frac{c}{b})}or \frac{a}{d}>1or a>d Answer is B.
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Re: a,b,c and d inequality [#permalink]
02 Aug 2010, 20:47
According to stmt2 (a/b) > 1.
So, a number greater than 1 multiplied with (c/b) will be greater than (c/b)
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Re: a,b,c and d inequality
[#permalink]
02 Aug 2010, 20:47
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