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CEO
Joined: 15 Aug 2003
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if a, b, c are odd integers , which of the following CANNOT [#permalink]
 08 Sep 2003, 15:29
if a, b, c are odd integers , which of the following CANNOT be an odd
integer?
a. a^2bc
b. 3a^3b^3C^5
c. a+b+c
d. 4c/(b+a)
e. a(3(b+c))
Do you guys have any specific way to start off these kinda questions...
or you just check em one by one
if i have to pick values for everyone...thats too much time!
thanks
praetorian
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Senior Manager
Joined: 22 May 2003
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You have to know these precious rules:
O*O=O
E*O=O*E=E
E*E=E
same for /
O+O=E
O+E=E+O=O
E+E=E
same for -
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Senior Manager
Joined: 22 Aug 2003
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I will just add to what Martin said. We need to find which of the given numbers CANNOT be odd (i.e. it is always even) given that a,b,c are odd integers. So u have to find which of the given choices is always even.
Just remember the basic rules of numbers (as martin wrote)
Product of even number with any integer is always even and some of two odds is always even.
Then just a glance of choices will tell that answer is (E).
-Vicks
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Intern
Joined: 17 Aug 2003
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Location: USA
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MartinMag wrote: You have to know these precious rules:
O*O=O
E*O=O*E=E
E*E=E
same for /
O+O=E
O+E=E+O=O
E+E=E
same for -
What are the rules for /
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Senior Manager
Joined: 22 May 2003
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camel wrote: MartinMag wrote: You have to know these precious rules:
O*O=O
E*O=O*E=E
E*E=E
same for /
O+O=E
O+E=E+O=O
E+E=E
same for - What are the rules for / Rules for (/) same as rules for (*)
Rules for (-) same as rules for (+)
Hope it helps
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Senior Manager
Joined: 22 May 2003
Posts: 341
Location: Uruguay
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Good point. I guess then that the rules for / are the same for * PROVIDED that the division is an integer.
The problem in question asks which one CANNOT be an integer. In choice D 4c/(b+a) COULD be an integer, but aplying the rules you find that it CANNOT be an ODD.
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