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If a>b, is a>c? 1.a/b>c/b 2.5ab>6bc

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Intern
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If a>b, is a>c? 1.a/b>c/b 2.5ab>6bc [#permalink] New post 08 May 2003, 15:26
If a>b, is a>c?

1.a/b>c/b

2.5ab>6bc
Intern
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 [#permalink] New post 13 May 2003, 15:01
I think the answer is D, Either.

Multiplying or dividing both sides of an inequality gives an equivalent inequality.

Therefore

a/b>c/b is equivalent to a>c
AND
5ab>6bc is equivalent to 5a>6c or a>6/5c

Therefore

a>c in either case.
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 [#permalink] New post 13 May 2003, 17:06
could someone explain the logic of E to me? I'm missing something obviously.....
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 [#permalink] New post 13 May 2003, 18:50
Suneeta,

This is a very common trap.......if ab>ac, this does not imply that b>c.
here is the explanation

suppose a=1, b=3, c=2, which implies that ab>ac

in this case, b>c

however if a=-1, b=2 and c=3, which again implies that ab>ac

but in this case b is not greater than c

so it depends on the sign of the common variable on both sides. you can multiply or divide a variable on both sides of the inequality, only if you know the sign of an inequality. Remember, multiplying or dividing by a negative number changes the inequality sign.

hope that helps
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 [#permalink] New post 14 May 2003, 08:11
Thanks a lot! That definitely helps...
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 [#permalink] New post 14 May 2003, 10:04
Ans : E

Another way to look at it :

1)
if b is +ve then : a>c
if b is -ve then : c>a
Insuff

2)
if b+ve then : 5a > 6c
if b -ve then : 5a < 6c
Insuff

Combined : a/b*(1+5b^2) > c/b*(1+6b^2)

if b=1, then 6a>7c, thus a>c
if b=-1, then 6a<7c thus c couldbe greater than a
try with fractions are ans is insufficient
Insuff

Ans : E

Last edited by tzolkin on 16 May 2003, 10:51, edited 1 time in total.
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 [#permalink] New post 03 Jul 2005, 21:38
reusing the question...
  [#permalink] 03 Jul 2005, 21:38
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