Hello,

lets take each one given |a| > |b|

a) ab > 0 Not allways . If a,b are both negative then true, either positive then fails.

b) |a|+b > 0Since we know that absolute value of a is greater than absolute value of b , we can for sure say that |a| > b

The above would fail only if |a| = |b| or |b| > |a| so

B is the answer because -- given |a| > |b|

c) a+|b| > 0Not always consider a = -7 and b = -5 (given |a| > |b|)

-7 + 5 = -2 <0 hence not possible ;

d) |b|/a > 0not always if a is positive then true, if a is negative then false because for all values of {b} except zero |B| is always positive

e) |a|*b > 0not always if b is positive then true, if b is negative then false because for all values of {a} except zero |a| is always positive

Hope my explanation was helpful.

OA is BRegards

Raghav.V

Consider Kudos if you think my explanation was helpful