Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: If A=BC, is A>B ? [#permalink]
28 Jan 2013, 02:04

1

This post received KUDOS

Expert's post

If A=BC, is A>B ?

Since A=BC, then the question can be re-written as "is BC>B?" --> is B(C-1)>0? Basically the question asks whether B and C-1 have the same sign.

(1) 0<C<1 --> C-1<0. We don't know the sign of B. Not sufficient.

For example, if A=1/4 and B=C=1/2, then A<B but if A=-1/2, B=-1 and C=1/2, then A>B. Not sufficient.

(2) A>0. If A=B=C=1, then A=B but if A=1 and B=C=-1, then A>B. Not sufficient.

(1)+(2) From above we have that both A and C are positive, hence B must also be positive (from A=BC). So, we have that B>0 and C-1<0: B and C-1 have opposite signs, therefore B(C-1)<0 (we have a definite NO answer to the question). Sufficient.

Answer: C.

P.S. Please read carefully and follow: rules-for-posting-please-read-this-before-posting-133935.html Pay attention to the rules #1 (Choose the Right Forum) and #3 (the name of a topic (subject field) MUST be the first 40 characters (~the first two sentences) of the question). _________________

Starting with the easy statement: Statement 2 says that A>0, but no information has been given about B. So it is insufficient. Statement 1 says that C is a gractional value, lying between 0 and 1. No info about A and B. Clearly Insufficient. The answer has to be either C or E. On combining the statements we get: A>0 and 0<C<1. Do notice that A and B can be fractional values also. Now consider, A=0.1 and C=0.9, since A=BC therefore B=1/9. Here B>A. Now consider, A=0.9 and C=0.1, since A=BC, therefore B=9. Here also B>A. If one takes integer values of A, then also B>A. Hence sufficient. +1C _________________

No, B is not sufficient. it just tells A>0 , But you dont know anything about B/C individually.

Each statement alone is insufficient, clearly as none has more than one variable when we need relation between 2.

On combining, we get A>0 and 0<C<1. Since A, C>0 thus B>0

Notice, multiplication by a fraction will alsways result in a lower number for any postive number. Therefore if A =BC where 0<C<1 then A <B Sufficient. _________________

Re: If A=BC, is A>B ? [#permalink]
29 Jan 2013, 21:43

My Say

(1). C belongs to (0,1)

=> C is +ve => A and B should have same signs

Case 1: A,B are -ve => A=-3 and B=-4 => A>B Case 2: A,B are +ve => A=3 and B=4 => A<B

=>Insufficient

(2). A>0

Case 1: B is -ve => A=3 , B=-1 => A>B Case 2 : B is +ve => A=3 , B=4 => A <B =>Insufficient

Combined A>0 => Case 2 only of Statement 1 Hence (C). _________________

Rgds, TGC! _____________________________________________________________________ I Assisted You => KUDOS Please _____________________________________________________________________________

I´ve done an interview at Accepted.com quite a while ago and if any of you are interested, here is the link . I´m through my preparation of my second...

It’s here. Internship season. The key is on searching and applying for the jobs that you feel confident working on, not doing something out of pressure. Rotman has...