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Re: If A=BC, is A>B ? [#permalink]
28 Jan 2013, 02:04
This post received KUDOS
If A=BC, is A>B ?
Since A=BC, then the question can be re-written as "is BC>B?" --> is B(C-1)>0? Basically the question asks whether B and C-1 have the same sign.
(1) 0<C<1 --> C-1<0. We don't know the sign of B. Not sufficient.
For example, if A=1/4 and B=C=1/2, then A<B but if A=-1/2, B=-1 and C=1/2, then A>B. Not sufficient.
(2) A>0. If A=B=C=1, then A=B but if A=1 and B=C=-1, then A>B. Not sufficient.
(1)+(2) From above we have that both A and C are positive, hence B must also be positive (from A=BC). So, we have that B>0 and C-1<0: B and C-1 have opposite signs, therefore B(C-1)<0 (we have a definite NO answer to the question). Sufficient.
Starting with the easy statement: Statement 2 says that A>0, but no information has been given about B. So it is insufficient. Statement 1 says that C is a gractional value, lying between 0 and 1. No info about A and B. Clearly Insufficient. The answer has to be either C or E. On combining the statements we get: A>0 and 0<C<1. Do notice that A and B can be fractional values also. Now consider, A=0.1 and C=0.9, since A=BC therefore B=1/9. Here B>A. Now consider, A=0.9 and C=0.1, since A=BC, therefore B=9. Here also B>A. If one takes integer values of A, then also B>A. Hence sufficient. +1C _________________
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