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If a certain toy store's revenue in November was 2/5 of its [#permalink]
25 Jun 2012, 01:36

Expert's post

5

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

45% (medium)

Question Stats:

60% (02:27) correct
40% (01:29) wrong based on 603 sessions

If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?

(A) 1/4 (B) 1/2 (C) 2/3 (D) 2 (E) 4

Diagnostic Test Question: 8 Page: 21 Difficulty: 600

Re: If a certain toy store's revenue in November was 2/5 of its [#permalink]
25 Jun 2012, 01:36

3

This post received KUDOS

Expert's post

1

This post was BOOKMARKED

SOLUTION

If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?

(A) 1/4 (B) 1/2 (C) 2/3 (D) 2 (E) 4

Probably, for most people it would be easier to solve such kind of questions by picking numbers.

Notice that January is linked with November and November is linked with December. So, we should pick some smart number for December's revenue. Since the denominators in the question are 5 and 4, the let say December's revenue was 20 (the least common multiple of 4 and 5). So, we have that:

Revenue in December = 20; Revenue in November = 20*2/5 = 8; Revenue in January = 8*1/4 = 2;

The average of 8 and 2 is 5, so the store's revenue in December was 20/5=4 times that value.

Re: If a certain toy store's revenue in November was 2/5 of its [#permalink]
25 Jun 2012, 03:29

1

This post received KUDOS

Hi,

Lets say, revenue in November = N was 2/5 of its revenue in December = D revenue in January = J As per given data, N = (2/5)D J = (1/4)N = 1/4 * 2/5 *D = (1/10)D

Re: If a certain toy store's revenue in November was 2/5 of its [#permalink]
29 Jun 2012, 02:05

Expert's post

SOLUTION

If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?

(A) 1/4 (B) 1/2 (C) 2/3 (D) 2 (E) 4

Probably, for most people it would be easier to solve such kind of questions by picking numbers.

Notice that January is linked with November and November is linked with December. So, we should pick some smart number for December's revenue. Since the denominators in the question are 5 and 4, then let say December's revenue was 20 (the least common multiple of 4 and 5). So, we have that:

Revenue in December = 20; Revenue in November = 20*2/5 = 8; Revenue in January = 8*1/4 = 2;

The average of 8 and 2 is 5, so the store's revenue in December was 20/5=4 times that value.

Re: If a certain toy store's revenue in November was 2/5 of its [#permalink]
16 Jul 2014, 18:48

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Re: If a certain toy store's revenue in November was 2/5 of its [#permalink]
06 Aug 2015, 05:24

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Re: If a certain toy store's revenue in November was 2/5 of its [#permalink]
06 Aug 2015, 06:16

Expert's post

Bunuel wrote:

If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?

(A) 1/4 (B) 1/2 (C) 2/3 (D) 2 (E) 4

Diagnostic Test Question: 8 Page: 21 Difficulty: 600

If N = 2/5 D and J = 1/4N, we should put all expressions into a common variable. Let's use D. D =D; N =2/5D; and J = 1/10D. Assuming D =10, we now have N = 4 and J = 1. The average of 4 and 1 is 2.5 10 is 4 times greater than 2.5 Answer E is correct _________________

If a certain toy store's revenue in November was 2/5 of its [#permalink]
20 Nov 2015, 05:19

This can be solved even faster:

The revenue in November (N) is less than half the revenue in December (D). Therefore, December revenue is more than twice the November revenue: \(D>2N\)

The revenue in January (J) is even smaller than revenue in November. Consequently, the average of the two will be less than N: \(Average = (J+N)/2 < N\)

Therefore, December revenue will be far more than twice the average: \(D>2N>2*Average\)

The only option left is (E).

gmatclubot

If a certain toy store's revenue in November was 2/5 of its
[#permalink]
20 Nov 2015, 05:19

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