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If a certain toy store's revenue in November was 2/5 of its [#permalink]
25 Jun 2012, 01:36

Expert's post

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A

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Difficulty:

45% (medium)

Question Stats:

60% (02:29) correct
40% (01:29) wrong based on 486 sessions

If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?

(A) 1/4 (B) 1/2 (C) 2/3 (D) 2 (E) 4

Diagnostic Test Question: 8 Page: 21 Difficulty: 600

Re: If a certain toy store's revenue in November was 2/5 of its [#permalink]
25 Jun 2012, 01:36

1

This post received KUDOS

Expert's post

1

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SOLUTION

If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?

(A) 1/4 (B) 1/2 (C) 2/3 (D) 2 (E) 4

Probably, for most people it would be easier to solve such kind of questions by picking numbers.

Notice that January is linked with November and November is linked with December. So, we should pick some smart number for December's revenue. Since the denominators in the question are 5 and 4, the let say December's revenue was 20 (the least common multiple of 4 and 5). So, we have that:

Revenue in December = 20; Revenue in November = 20*2/5 = 8; Revenue in January = 8*1/4 = 2;

The average of 8 and 2 is 5, so the store's revenue in December was 20/5=4 times that value.

Re: If a certain toy store's revenue in November was 2/5 of its [#permalink]
25 Jun 2012, 03:29

Hi,

Lets say, revenue in November = N was 2/5 of its revenue in December = D revenue in January = J As per given data, N = (2/5)D J = (1/4)N = 1/4 * 2/5 *D = (1/10)D

Re: If a certain toy store's revenue in November was 2/5 of its [#permalink]
29 Jun 2012, 02:05

Expert's post

SOLUTION

If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?

(A) 1/4 (B) 1/2 (C) 2/3 (D) 2 (E) 4

Probably, for most people it would be easier to solve such kind of questions by picking numbers.

Notice that January is linked with November and November is linked with December. So, we should pick some smart number for December's revenue. Since the denominators in the question are 5 and 4, then let say December's revenue was 20 (the least common multiple of 4 and 5). So, we have that:

Revenue in December = 20; Revenue in November = 20*2/5 = 8; Revenue in January = 8*1/4 = 2;

The average of 8 and 2 is 5, so the store's revenue in December was 20/5=4 times that value.

Re: If a certain toy store's revenue in November was 2/5 of its [#permalink]
16 Jul 2014, 18:48

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