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# If a code word is defined to be a sequence of different

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Senior Manager
Joined: 08 Jun 2004
Posts: 499
Location: Europe
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If a code word is defined to be a sequence of different [#permalink]  25 Apr 2006, 11:21
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Question Stats:

100% (02:27) correct 0% (00:00) wrong based on 0 sessions
If a code word is defined to be a sequence of different letters chosen from the 10 letters A, B, C, D, E, F, G, H, I, and J, what is the ratio of the number of 5-letter code words to the number of 4-letter code words?

A. 5 to 4
B. 3 to 2
C. 2 to 1
D. 5 to 1
E. 6 to 1

Manager
Joined: 23 Jan 2006
Posts: 192
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E. 6 to 1

5P10/6P10 =

10*9*8*7*6
--------------
10*9*8*7

=6
VP
Joined: 29 Dec 2005
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Re: PS: sequence (code words) [#permalink]  25 Apr 2006, 21:43
M8 wrote:
If a code word is defined to be a sequence of different letters chosen from the 10 letters A, B, C, D, E, F, G, H, I, and J, what is the ratio of the number of 5-letter code words to the number of 4-letter code words?

A. 5 to 4
B. 3 to 2
C. 2 to 1
D. 5 to 1
E. 6 to 1

since order matters, use permutation.

= 10p5/10p4 = [(10x9x8x7x6x5!)/5!]/[(10x9x8x7x6!)/6!) = 6
Senior Manager
Joined: 08 Jun 2004
Posts: 499
Location: Europe
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Kudos [?]: 20 [0], given: 0

Great job guys, OA is E.
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