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If a code word is defined to be a sequence of different letters chosen

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If a code word is defined to be a sequence of different letters chosen [#permalink] New post 09 Jul 2009, 01:08
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Question Stats:

58% (01:21) correct 43% (01:17) wrong based on 42 sessions
If a code word is defined to be a sequence of different letters chosen from the 10 letters A, B, C, D, E, F, G, H, I, and J, what is the ratio of the number of 5-letter code words to the number of 4-letter code words?

A. 5 to 4
B. 3 to 2
C. 2 to 1
D. 5 to 1
E. 6 to 1

OPEN DISCUSSION OF THIS QUESTION IS HERE: if-a-code-word-is-defined-to-be-a-sequence-of-different-126652.html
[Reveal] Spoiler: OA
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Re: If a code word is defined to be a sequence of different letters chosen [#permalink] New post 09 Jul 2009, 08:19
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I’m not too good at these, but I’ll give it a shot. The wording of the question seems like order should not matter, but I tried solving that way and it didn't work. In this case ORDER MATTERS. I am unable to articulate why. Someone please explain for all of our edification.

Method #1: Using the permutation formula
# of 5 letter code words:
nPr = n! / (n – r)! = 10! / (10 – 5)! = 10*9*8*7*6

# of 4 letter code words:
nPr = 10! / (10 – 4)! = 10*9*8*7

# of 5 words / # of 4 words = (10*9*8*7*6)/(10*9*8*7) = 6 = 6/1

Answer is E.

Method #2: Using the “slots” method

# of 5 letter code words:
There are 5 empty slots below. For the first slot, you have an option of choosing 10 different letters. So fill that slot in with 10. For the second slot, you now have 9 letters to choose from. For the third slot, you have 8 letters. Keep going until you fill in all the slots and multiply all the numbers. That gives you the total # of possibilities.
__ __ __ __ __

10 * 9 * 8 * 7 * 6

# of 4 letter code words:
__ __ __ __

10 * 9 * 8 * 7

Ratio = (10*9*8*7*6)/(10*9*8*7) = 6 = 6/1

Answer E.
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Re: If a code word is defined to be a sequence of different letters chosen [#permalink] New post 13 Mar 2015, 12:55
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Re: If a code word is defined to be a sequence of different letters chosen [#permalink] New post 13 Mar 2015, 20:34
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ankur55 wrote:
If a code word is defined to be a sequence of different letters chosen from the 10 letters A, B, C, D, E, F, G, H, I, and J, what is the ratio of the number of 5-letter code words to the number of 4-letter code words?

A. 5 to 4
B. 3 to 2
C. 2 to 1
D. 5 to 1
E. 6 to 1



Notice that as we are dealing with code words then the order of the letters matters.

# of ways to choose 5 different letters out of given 10 letters when the order of chosen letters matters (as for example code word ABCDE is different from BCDEA) is \(P^5_{10}\);

# of ways to choose 4 different letters out of given 10 letters when the order of chosen letters matters is \(P^4_{10}\);

\(Ratio=\frac{P^5_{10}}{P^4_{10}}=\frac{10!}{5!}*\frac{6!}{10!}=\frac{6}{1}\).

Answer: E.

OPEN DISCUSSION OF THIS QUESTION IS HERE: if-a-code-word-is-defined-to-be-a-sequence-of-different-126652.html
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Re: If a code word is defined to be a sequence of different letters chosen   [#permalink] 13 Mar 2015, 20:34
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