Total comb. for a committee of 3 - Total comb. a committee of 3 including a married couple
10C3 - (5C1*8C1)
Please elaborate 5C1*8C1 in the above explaination?
There are 5 couples and I want to know how many ways I could pick out one couple....thus 5C1.
Since two couples are picked, I want to know how many ways I could pick the 1 out of the people that's left...thus (10-2)C1
Don't be afraid to take a flying leap of faith.. If you risk nothing, than you gain nothing...