Yogendras wrote:

Total comb. for a committee of 3 - Total comb. a committee of 3 including a married couple

10C3 - (5C1*8C1)

Please elaborate 5C1*8C1 in the above explaination?

There are 5 couples and I want to know how many ways I could pick out one couple....thus 5C1.

Since two couples are picked, I want to know how many ways I could pick the 1 out of the people that's left...thus (10-2)C1

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