Professor wrote:

M8 wrote:

If a committee of 3 people is to be selected from among 5 married couples so that the committee does not include two people who are married to each other, how many such committees are possible?

A. 20

B. 40

C. 50

D. 80

E. 120

total = 10c3 = 120

no of ways 3 people with 2 couple and a single can be selected = 5 x8 = 40

so, no of ways 3 people with all individual singles can be selected = 120 - 40 = 80

Nice explanation prof

However, I was wondering..what is wrond wid....10C1 * 8C1 * 6C1

10C1---> take one person out of 10

8C1-->leave the spouse of the person selected in above round..

6C1--->leave the spuse of pwerson selected above...

Plz tell what m I missing..