TOUGH GUY wrote:
Can someone explain the second part of the question?
This sound complex: choosing 3 people with a married couple
No of ways of choosing 3 people with a married couple in it = 5 X 8C1=40
You have to choose 3 people in which there is a couple. There are 5 couples in all, so 2 out of the 3 people must be one out of these 5 couples. Since there are exactly 5 couples, there are exactly 5 ways in which you could choose a couple.
Now after we chose a couple there are 8 people left, from which we must choose exactly 1 more person to make the total number of people in our group equal to 3. Since there are 8 people, and we need to choose 1, there are 8C1 ways of choosing one person.
This gives us 5 x 8C1. PM me if you want to discuss this further.