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# If A is the center of the circle shown above and AB=BC=CD,

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Senior Manager
Joined: 22 Aug 2003
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If A is the center of the circle shown above and AB=BC=CD, [#permalink]

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25 Sep 2003, 05:40
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

10. If A is the center of the circle shown above and AB=BC=CD, what is the value of x?
(A) 15
(B) 30
(C) 45
(D) 60
(E) 75
ps: I am not able to copy the geometry drawing, so i am sending it as a file. btw, how is possible to copy figures/drawing in the mail itself.
Senior Manager
Joined: 22 Aug 2003
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25 Sep 2003, 06:00
Correct.
stolyar how did u arrived at the answer. I used properties of angles in circle. (angle subteded by an arc at center is twice the angle that it substends at any other point on the circle).
Just seeing if there is a shorter way.
SVP
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25 Sep 2003, 06:16
ABCD is a rhombus. AB=AC=AD — they are all radii. Therefore, ABC is an equilateral triangle. 2X=angle A=60, so X=30
Senior Manager
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25 Sep 2003, 06:20
too good...
i missed equilateral stuff and ended up wasting 4-5 minutes in solving it.
thanks stolyar
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# If A is the center of the circle shown above and AB=BC=CD,

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