Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: If A is the center of the circle shown above [#permalink]
25 Feb 2012, 11:41

2

This post received KUDOS

Expert's post

2

This post was BOOKMARKED

TheRob wrote:

If A is the center of the circle shown above (see attachment) and AB = BC = CD, What is the value of x?

A. 15 B. 30 C. 45 D. 60 E. 75

Attachment:

The attachment Circle - original.PNG is no longer available

(I tried to draw it the best I could sorry for the inconvenience)

Look at the diagram below:

Attachment:

Circle.PNG [ 26.39 KiB | Viewed 10036 times ]

Given that AB = BC = CD, also since AB is the radius then AB = AC = AD = radius, so we have that: AB = BC = CD = AC = AD, so basically we have two equilateral triangles ABC and ACD with common base of AC (ABC and ACD are mirror images of each other). Line segment BD cuts the angle ABC in half and since all angles in equilateral triangle equal to 60 degrees then x=60/2=30 degrees.

Re: If A is the center of the circle shown above [#permalink]
27 Feb 2012, 07:42

1

This post received KUDOS

Expert's post

pbull78 wrote:

bunuel ,

how can we say that line segment BD cuts the angle ABC in half which property is this , can u expalin me? thanks

ABC and ACD are two equilateral triangles, which are mirror images of each other if you join vertices B and D, the segment BD must cut AC, the common base, in half. Which makes BD perpendicular bisector of AC --> so BO is a hight, median, and bisector of angle ABC (O being intersection point of BD and AC).

Re: If A is the center of the circle shown above [#permalink]
27 Feb 2012, 07:43

This is a proper rhombus... and this is one of the property of rhombus... that they bisect the diagonals in half.. and the diagonals bisect the angles in half...

also Angle (DAC is 120 degree ) and Triangle DAC is an isosceles triangle.. with base BD... hence angle ABD is 30

Re: If A is the center of the circle shown above (see attachment [#permalink]
28 Oct 2013, 08:42

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Re: If A is the center of the circle shown above (see attachment [#permalink]
22 Jun 2014, 08:38

Bunuel wrote:

aakrity wrote:

we are given that AB=BC=CD AB is the radius of the circle, so AB=AD

This makes ABCD a square. Therefore, BD and AC are the diagonals of the square. Angle A, B, C, D = 90 and hence x=45

Why is this not considered that ABCD is a square?

ABCD is not a square it's a rhombus (the diagonals are not equal).

Bunnel,

So Diagonals are 'angle bisectors' both in a Rhombus (not congruent here) and a Square. But it's not the case in a rectangle where they are congruent and perpendicular bosectors alone. Is my understanding accurate? I've read that every point on an angle bisector is equidistant from both the adjacent sides. Is there any other way to identify whether a diagonal is also an angle bisector?

Re: If A is the center of the circle shown above (see attachment [#permalink]
22 Jun 2014, 14:55

Expert's post

Kconfused wrote:

Bunuel wrote:

aakrity wrote:

we are given that AB=BC=CD AB is the radius of the circle, so AB=AD

This makes ABCD a square. Therefore, BD and AC are the diagonals of the square. Angle A, B, C, D = 90 and hence x=45

Why is this not considered that ABCD is a square?

ABCD is not a square it's a rhombus (the diagonals are not equal).

Bunnel,

So Diagonals are 'angle bisectors' both in a Rhombus (not congruent here) and a Square. But it's not the case in a rectangle where they are congruent and perpendicular bosectors alone. Is my understanding accurate? I've read that every point on an angle bisector is equidistant from both the adjacent sides. Is there any other way to identify whether a diagonal is also an angle bisector?

Thank you

All is true, except that the diagonals in rectangle are no perpendicular to each other. They bisect each other but not at a right angle. _________________

Re: If A is the center of the circle shown above (see attachment [#permalink]
17 Sep 2015, 08:28

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

On September 6, 2015, I started my MBA journey at London Business School. I took some pictures on my way from the airport to school, and uploaded them on...

When I was growing up, I read a story about a piccolo player. A master orchestra conductor came to town and he decided to practice with the largest orchestra...

A site for the partners of MBA candidates : A website we are creating for the better halves of the MBA candidates and the candidates themselves to know “the...

A week ago we were informed of our pre program preparation for Entrepreneurship and Finance… 2.5 months to go and we are already busy with our studies… Where...