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Re: If a, m and n are positive integers, is n^(2a) a multiple of [#permalink]
06 Jul 2014, 21:27

1

This post was BOOKMARKED

The question basically asks if n^2a/m^a =integer,is (n^a.n^a)/m^a =integer,is (n/m)^a.n^a=integer,since n and a are positive integer,it will always be an integer,so the question really is n a multiple of m then only (n/m)^a.n^a=integer

Statement 1 n/(m/2)=integer↪2n/m=integer↪n=1,m=2 then n/m≠integer↪↪but n=2,m=1,then n/m=integer…not sufficient

Re: If a, m and n are positive integers, is n^(2a) a multiple of [#permalink]
08 Jul 2015, 01:28

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